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agasfer [191]
3 years ago
9

PLEASE HELP ON MY LAST GEOMETRY PROBLEM!!

Mathematics
2 answers:
Alexxx [7]3 years ago
5 0

Answer:

area of circle having radius 3

is πr²=π*3²=9π square units

area of circle having radius 2

=πr²=π×2²=4π square units

again

area of big circle having radius [3+2]=5 units

=πr²=π×5²=25π square units

Now

area of shaded region=25π-4π-9π=12π or 37.7square units.

Andreas93 [3]3 years ago
5 0

Answer:

12π units² or 37.7 units²

Step-by-step explanation:

Find the area of the 3 circles and subtract the areas of the two smallest ones.

Biggest circle area: π((3(2)+2(2))/2)² = π((6+4)/2)² = π(5²) = 25π units²

2nd Biggest circle area: π(3)² = 9π units²

Smallest circle area: π(2)² = 4π units²

Shaded area: 25π - (9π + 4π) = 25π - 13π = 12π units² or 37.7 units²

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5) In a certain supermarket, a sample of 60 customers who used a self-service checkout lane averaged 5.2 minutes of checkout tim
Ne4ueva [31]

Answer:

\S^2_p =\frac{(60-1)(3.1)^2 +(72 -1)(2.8)^2}{60 +72 -2}=8.643

S_p=2.940

t=\frac{(5.2 -6.1)-(0)}{2.940\sqrt{\frac{1}{60}+\frac{1}{72}}}=-1.751

df=60+72-2=130

p_v =P(t_{130}

Assuming a significance level of \alpha=0.05 we have that the p value is lower than this significance level so then we can conclude that the mean for checkout time is significantly less for people who use the self-service lane

Step-by-step explanation:

Data given

Our notation on this case :

n_1 =60 represent the sample size for people who used a self service

n_2 =72 represent the sample size for people who used a cashier

\bar X_1 =5.2 represent the sample mean for people who used a self service

\bar X_2 =6.1 represent the sample mean people who used a cashier

s_1=3.1 represent the sample standard deviation for people who used a self service

s_2=2.8 represent the sample standard deviation for people who used a cashier

Assumptions

When we have two independent samples from two normal distributions with equal variances we are assuming that  

\sigma^2_1 =\sigma^2_2 =\sigma^2

The statistic is given by:

t=\frac{(\bar X_1 -\bar X_2)-(\mu_{1}-\mu_2)}{S_p\sqrt{\frac{1}{n_1}+\frac{1}{n_2}}}

And t follows a t distribution with n_1+n_2 -2 degrees of freedom and the pooled variance S^2_p is given by this formula:

\S^2_p =\frac{(n_1-1)S^2_1 +(n_2 -1)S^2_2}{n_1 +n_2 -2}

System of hypothesis

Null hypothesis: \mu_1 \geq \mu_2

Alternative hypothesis: \mu_1 < \mu_2

This system is equivalent to:

Null hypothesis: \mu_1 - \mu_2 \geq 0

Alternative hypothesis: \mu_1 -\mu_2 < 0

We can find the pooled variance:

\S^2_p =\frac{(60-1)(3.1)^2 +(72 -1)(2.8)^2}{60 +72 -2}=8.643

And the deviation would be just the square root of the variance:

S_p=2.940

The statistic is given by:

t=\frac{(5.2 -6.1)-(0)}{2.940\sqrt{\frac{1}{60}+\frac{1}{72}}}=-1.751

The degrees of freedom are given by:

df=60+72-2=130

And now we can calculate the p value with:

p_v =P(t_{130}

Assuming a significance level of \alpha=0.05 we have that the p value is lower than this significance level so then we can conclude that the mean for checkout time is significantly less for people who use the self-service lane

5 0
3 years ago
What is the distance between the 2 points? Round to the nearest tenths place.
Anna71 [15]

Check the picture below.

7 0
3 years ago
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Ao se olhar para a história da Álgebra, desde os primórdios quando o objeto de estudo eram equações algébricas específicas até o
professor190 [17]

Answer:

44

Step-by-step explanation:

Trust

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3 years ago
Find the value of n .<br> 6/n = 24/28<br> y = ___.
il63 [147K]

Answer:

n=7

Step-by-step explanation:

Cross multiply, isolate the variable, and divide by the coefficient to solve.

\frac{6}{n}=\frac{24}{28} \\ \\ 24n=168 \\ \\ n=7

Plug back in to check.

\frac{6}{7}=0.857142857 \\ \\ \frac{24}{28} =0.857142857

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What is the equation of the line that is parallel to the given line and passes through the point (2, 3)?
Lelechka [254]

Answer:

(-4,0)(4,-4)

slope(m) = (-4 - 0) / (4 - (-4) = -4/(4 + 4) = -4/8 = -1/2. A parallel line will have the same slope.

y = mx + b

slope(m) = -1/2

(2,3)...x = 2 and y = 3

now we sub and find b, the y int

3 = -1/2(2) + b

3 = -1 + b

3 + 1 = b

4 = b

y = -1/2x + 4

1/2x + y = 4....multiply by 2

x + 2y = 8 <== ur parallel line

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3 years ago
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