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Nadya [2.5K]
3 years ago
15

6(n-3)-2n=10 solve n

Mathematics
2 answers:
BARSIC [14]3 years ago
7 0
I got -2. i hope that’s correct
Naddika [18.5K]3 years ago
7 0

Answer:

n=7

Step-by-step explanation:

6(n-3)-2n=10

Distributive Property

6n-18-2n=10

Combine like terms

4n-18=10

Addition property of equality with -18; add -18 to both sides

4n=28

Division property of equality; divide 4 from both sides

n=7

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Pleaseeee help me solve this
Ulleksa [173]

Answer:

3/5 is the answer!

Step-by-step explanation:

y = 3x/5 also means y = 3/5 * x

Which means in y = mx form, the 3/5 = m

6 0
3 years ago
What will be the unit digit of the cube of a number ending with 9 ?
Bess [88]

Answer:

9

Step-by-step explanation:

If I’m understanding you correctly, the answer would be nine.  Any number with a 9 in the one’s place (unit digit) would still have a nine in that place after being cubed.

29³=24,389

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3 0
3 years ago
Read 2 more answers
M_6 is (2x – 5)º and m_8 is (x + 5)º.
HACTEHA [7]

m_6 + m_8 = 180º because they form a straight line.

So, (2x-5) + (x+5) = 180

    3x = 180

      x = 60

So, m_115º    (2•60 - 5 = 115)

Also, because the two lines are parallel m_6 = m_3 by alternate interior angles.

So, m_3 = 115º

4 0
3 years ago
What is 1-2sin^2x=sinx <br> Please show steps and find all solutions in interval [0,2pi)
Svetlanka [38]

Answer:

\large\boxed{x=\dfrac{3\pi}{2}\ \vee\ x=\dfrac{\pi}{6}\ \vee\ x=\dfrac{5\pi}{6}}

Step-by-step explanation:

1-2\sin^2x=\sin x\\\\\text{substitute}\ t=\sin x,\ t\in[-1,\ 1]\\\\1-2t^2=t\qquad\text{subtract t from both sides}\\\\-2t^2-t+1=0\qquad\text{change the signs}\\\\2t^2+t-1=0\\\\2t^2+2t-t-1=0\\\\2t(t+1)-1(t+1)=0\\\\(t+1)(2t-1)=0\iff t+1=0\ \vee\ 2t-1=0\\\\t+1=0\qquad\text{subtract 1 from both sides}\\\boxed{t=-1}\\\\2t-1=0\qquad\text{add 1 to both sides}\\2t=1\qquad\text{divide both sides by 2}\\\boxed{t=\dfrac{1}{2}}

\sin x=-1\to x=-\dfrac{\pi}{2}+2k\pi,\ k\in\mathbb{Z}\\\\\sin x=\dfrac{1}{2}\to x=\dfrac{\pi}{6}+2k\pi\ \vee\ x=\dfrac{5\pi}{6}+2k\pi,\ k\in\mathbb{Z}\\\\x\in[0,\ 2\pi)

x=-\dfrac{\pi}{2}\notin[0,\ 2\pi)\\\\x=-\dfrac{\pi}{2}+2\pi=\dfrac{3\pi}{2}\in[0,\ 2\pi)\\\\x=-\dfrac{\pi}{2}+4\pi=\dfrac{7\pi}{2}\notin[0,\ 2\pi)\\\\x=\dfrac{\pi}{6}\in[0,\ 2\pi)\\\\x=\dfrac{\pi}{6}+2\pi=\dfrac{13\pi}{6}\notin[0,\ 2\pi)\\\\x=\dfrac{5\pi}{6}\in[0,\ 2\pi)\\\\x=\dfrac{5\pi}{6}+2\pi=\dfrac{17\pi}{6}\notin[0,\ 2\pi)

4 0
4 years ago
I don’t understand this
mylen [45]
To solve for an unknown number, you have to keep isolating it till it is all alone:
A=P(1+rt)
(1+rt)=A/P
rt=A/P -1
r=(A/P-1)/t
7 0
3 years ago
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