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bekas [8.4K]
3 years ago
7

While working on a customer issue, your colleague calls and asks for help to resolve his issue. What should you do?A. Go ahead a

nd resolve his situation first B. Request the colleague to call after sometime C. Work on both the issues at the same time D. Tell your colleague to work on his own.
Computers and Technology
1 answer:
Lesechka [4]3 years ago
4 0

Answer:

Request the colleague to call after sometime

Explanation:

While working on a customer issue, your colleague calls and asks for help to resolve his issue. What should be done is to "Request the colleague to call after some time."

This is because,e in situations like that, it is believed that the customer should come first, and that is the purpose of being there. For employee to serve the customer. A colleague can easily link up with other employees to get his issues sorted, or simply wait.

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Pero pa montarlo aquí tengo la piezaDespacito 
Quiero respirar tu cuello despacito 
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Para que te acuerdes si no estás conmigoDespacito 
Quiero desnudarte a besos despacito 
Firmo en las paredes de tu laberinto 
Y hacer de tu cuerpo todo un manuscrito (sube, sube, sube)
(Sube, sube)Quiero ver bailar tu pelo 
Quiero ser tu ritmo 
Que le enseñes a mi boca 
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A complete program with the method ShowCar:

import java.util.Scanner; // header file

public class ShowChar

{

public static void main(String[] args)

{

String lnOfText;

int i;

Scanner input = new Scanner(System.in);

System.out.print("Enter a line of text:");

lnOfText = input.nextLine();

System.out.print(" Enter your index: ");

i = input.nextInt();

show_Char(lnOfText,i);

}

public static void show_Char(String str_a, int i)

{

System.out.print(str_a.charAt(i));

}

}

In this program, both the inputs ie. a sentence or line of text as well as the index position is obtained. A method is written to find the string at that particular position. Finally the method prints that character at the particular index.

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Write a class that uses DO-WHILE loops to perform the following steps:
Murrr4er [49]

Answer:

  1. import java.util.Scanner;
  2. public class Main {
  3.    public static void main(String[] args) {
  4.        Scanner input = new Scanner(System.in);
  5.        int firstNum, secondNum;
  6.        do{
  7.            System.out.print("Input first number: ");
  8.            firstNum = input.nextInt();
  9.            System.out.print("Input second number: ");
  10.            secondNum = input.nextInt();
  11.            for(int i= firstNum; i <= secondNum; i++){
  12.                if(i % 2== 1){
  13.                    System.out.print(i + " ");
  14.                }
  15.            }
  16.            System.out.println();
  17.            int evenSum = 0;
  18.            for(int i= firstNum; i <= secondNum; i++){
  19.                if(i % 2== 0){
  20.                    System.out.print(i + " ");
  21.                    evenSum += i;
  22.                }
  23.            }
  24.            System.out.println();
  25.            System.out.println("Sum of even: " + evenSum);
  26.            System.out.println();
  27.            int squareOddSum = 0;
  28.            for(int i= firstNum; i <= secondNum; i++){
  29.                System.out.println(i + " : " + (i*i) );
  30.                if(i % 2 ==1){
  31.                    squareOddSum += i;
  32.                }
  33.            }
  34.            System.out.println();
  35.            System.out.println("Sum of squared odd number: " + squareOddSum);
  36.        }while(firstNum < secondNum);
  37.    }
  38. }

Explanation:

The solution code is written in Java.

Firstly, we create a Scanner object (Line 6) and use it get user input for first and second number (Line 10-13). We create a for loop and use modulus to check the current number is divisible by 2 and print out the odd number in loop (Line 15-19). We repeat the similar step to print the even number but at the same time, we also add the current number to evenSum variable and print the sum after the for loop (Line 23-33).

Next, we proceed to use another for loop to print out the number and their squares and then accumulate the sum of squares of all odd numbers (Line 36-41).

At last, we print out the sum of squares of odd numbers (Line 43).

In the do while loop condition,  if firstNum is smaller than secondNumber, the loop is ongoing (Line 45).

7 0
3 years ago
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