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rusak2 [61]
3 years ago
6

Of the choice below,access to with tab will start a power point presentation

Computers and Technology
1 answer:
kow [346]3 years ago
4 0

the menu and the toolbars
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To reduce costs and the environmental impact of commuting, your company decides to close a number of offices and to provide supp
kkurt [141]

Answer:

The description including its query is provided throughout the section of the elaboration elsewhere here.

Explanation:

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What is digital revolution?
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5 0
3 years ago
Give two reasons why cloud computing could be detrimental to a company.
dimulka [17.4K]

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Cyber-attacks.

Any time your data is stored on the cloud, you are at a higher risk of cyber-attack. Vulnerabilities such as DDoS attacks might occur and this single point of failure is in the cloud. As cloud computing continues to become more sophisticated, so do cyberattacks. As much as the security is right, hackers will go to any lengths to penetrate the systems.  


3 0
4 years ago
Hello again, just need help debugging-I honestly have no idea how the "isSpace" etc methods work and I've tried various syntaxes
Julli [10]

import java.util.Scanner;

public class JavaApplication81 {

   

   public static void main(String[] args) {

       Scanner s = new Scanner(System.in);

       System.out.println("Input the string");

       String as = s.nextLine();

       int cons = 0;

       int a = 0;

       int e = 0;

       int i = 0;

       int o = 0;

       int u = 0;

       int space = 0;

       int punc = 0;

       char c;

       int misc = 0;

       String punctuation = ".!,?";

       String consonants = "bcdfghjklmnpqrstvwxyz";

       for (int k = 0; k < as.length(); k++){

           c = as.charAt(k);

       if (Character.isWhitespace(c)){

           space ++;

       }

       else if (punctuation.indexOf(c) != -1){

           punc++;

       }

       else if (consonants.indexOf(c) != -1){

           cons++;

       }

       else if (c == 'a'){

           a++;

       }

       else if(c == 'e'){

           e++;

       }

       else if (c == 'i'){

           i++;

       }

       else if (c == 'o'){

           o++;

       }

       else if (c == 'u'){

           u++;

       }

       else{

           misc++;

       }

       

   }

       System.out.println(a+" a's");

       System.out.println(e+" e's");

       System.out.println(i+" i's");

       System.out.println(o+" o's");

       System.out.println(u+" u's");

       System.out.println(space+" spaces");

   

       System.out.println(punc+" punctuations");

       System.out.println(cons+" consonants");

       System.out.println(misc+" misc. (uppercase vowels, etc.");

   }

   

}

This is one example of how it could be done.

5 0
3 years ago
Please help me with this! I’m using Python 3
IgorLugansk [536]

Something like this?

h1 = int(input())

m1 = int(input())

s1 = int(input())

h2 = int(input())

m2 = int(input())

s2 = int(input())

s = h2*3600 + m2*60 + s2 - (h1*3600 + m1*60 + s1)

print(s)

3 0
3 years ago
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