Answer:
Step-by-step explanation:
those are weird numbers but where are the answer options
The quadratic equations and their solutions are;
9 ± √33 /4 = 2x² - 9x + 6.
4 ± √6 /2 = 2x² - 8x + 5.
9 ± √89 /4 = 2x² - 9x - 1.
4 ± √22 /2 = 2x² - 8x - 3.
Explanation:
- Any quadratic equation of the form, ax² + bx + c = 0 can be solved using the formula x = -b ± √b² - 4ac / 2a. Here a, b, and c are the coefficients of the x², x, and the numeric term respectively.
- We have to solve all of the five equations to be able to match the equations with their solutions.
- 2x² - 8x + 5, here a = 2, b = -8, c = 5. x = -b ± √b² - 4ac / 2a = -(-8) ± √(-8)² - 4(2)(5) / 2(2) = 8 ± √64 - 40/4. 24 can also be written as 4 × 6 and √4 = 2. So x = 8 ± 2√6 / 2×2= 4±√6/2.
- 2x² - 10x + 3, here a = 2, b = -10, c = 3. x =-b ± √b² - 4ac / 2a =-(-10) ± √(-10)² - 4(2)(3) / 2(4) = 10 ± √100 + 24/4. 124 can also be written as 4 × 31 and √4 = 2. So x = 10 ± 2√31 / 2×2 = 5 ± √31 /2.
- 2x² - 8x - 3, here a = 2, b = -8, c = -3. x = -b ± √b² - 4ac / 2a = -(-8) ± √(-8)² - 4(2)(-3) / 2(2) = 8 ± √64 + 24/4. 88 can also be written as 4 × 22 and √4 = 2. So x = 8 ± 2√22 / 2×2 = 4± √22/2.
- 2x² - 9x - 1, here a = 2, b = -9, c = -1. x = -b ± √b² - 4ac / 2a = -(-9) ± √(-9)² - 4(2)(-1) / 2(2) = 9 ± √81 + 8/4. x = 9 ± √89 / 4.
- 2x² - 9x + 6, here a = 2, b = -9, c = 6. x = -b ± √b² - 4ac / 2a = -(-9) ± √(-9)² - 4(2)(6) / 2(2) = 9 ± √81 - 48/4. x = 9 ± √33 / 4 .
so you are going to use the Pythagorean theorem on the smaller triangle to find the connecting side's length
now you can find the bigger triangle's hypotenuse
c=4
Answer:
D. 12°
Step-by-step explanation:
80° + 5x = 140°
or, 5x = 140° - 80°
or, x = 60°/5
:. = 12° <em><u>Ans</u></em>
Answer:
5 units
Step-by-step explanation:
If point T is on the line segment SU, then ST + TU = SU.
Given
TU = 4x + 1
SU = 8
ST = 3x
To get TU, we need to get the value of x first. To get x, we will substitute the given parameters into the formula;
3x+4x+1 = 8
7x+1 = 8
subtract 1 from both sides
7x+1-1 = 8-1
7x = 7
divide both sides by 7
7x/7 = 7/7
x = 1
Substitute x = 1 into the length TU
Since TU = 4x+1
TU = 4(1)+1
TU = 5
Hence the numerical length of TU is 5 units
