Answer:
x = 3 sqrt 2
Step-by-step explanation:
We know that this is a 45, 45m 90 special right triangle. In this special right triangle the side lengths are x, x and the hypotenuse is x sqrt 2 (we can prove this using pythagoreans theorem). 6 is the hypotenuse, meaning that it is equal to x sqrt 2:
6 = x sqrt 2
x = 6/sqrt 2
Rationalize the denominator:
x = (6 sqrt 2)/2
x = 3 sqrt 2
AD = 42-x
The bisector of an angle of a triangle divides the opposite side into segments that are proportional to the adjacent sides ⇒
AB/BC = AD/DC
36/27 = (42-x)/x
36x = 27(42-x)
36x = 1134 - 27x
36x + 27x = 1134
63x = 1134
x = 1134/63
x = 18
Answer:
the answer is no solution.
<h3>3
Answers: Choice D, Choice E, Choice F</h3>
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Explanation:
The inequality 6x - 10y ≥ 9 solves to y ≤ (3/5)x - 9/10 when you isolate y.
Graph the line y = (3/5)x - 9/10 and make this a solid line. The boundary line is solid due to the "or equal to" as part of the inequality sign. We shade below the boundary line because of the "less than" after we isolated for y.
Now graph all of the points given as I've done so in the diagram below. The points in the blue shaded region, or on the boundary line, are part of the solution set. Those points are D, E and F.
We can verify this algebraically. For instance, if we weren't sure point E was a solution or not, we would plug the coordinates into the inequality to get...
6x - 10y ≥ 9
6(5) - 10(2) ≥ 9 .... plug in (x,y) = (5,2)
30 - 20 ≥ 9
10 ≥ 9 ... this is a true statement
Since we end up with a true statement, this verifies point E is one of the solutions. I'll let you check points D and F.
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I'll show an example of something that doesn't work. Let's pick on point A.
We'll plug in (x,y) = (-1,1)
6x - 10y ≥ 9
6(-1) - 10(1) ≥ 9
-6 - 10 ≥ 9
-16 ≥ 9
The last inequality is false because -16 is smaller than 9. So this shows point A is not a solution. Choices B and C are non-solutions for similar reasons.