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3 years ago

Which shows the best path to find the number of centimeters in 1 yard?

Mathematics

1 answer:

Morgarella [4.7K]3 years ago

3 0

Answer:

yards feet centimeters

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Y = -5x + 1 graph the equation by making a table of values. Use 3 values of x.

Naily [24]

Answer:

Table -

x=-1 y= 6

x=0 y= 1

x=1 y= -4

Step-by-step explanation:

Answers are found by plugging in any 3 values of x

3 0

3 years ago

What is a angle for 40?

Vika [28.1K]

What are you trying to ask can you post a pic with the exact question?

8 0

3 years ago

There was d dollars in the savings account when mr Duane withdrew $45 from the account. Then me Duane deposited and additional $

Basile [38]

What are you asking ???
Write it in an equation ???
d+65-45=Final Balance
D+20=Final Balance
Not sure if this is what you're looking for !

6 0

3 years ago

three bags of sweets weigh 27/4 kg. two of them have the same weight and the third bag is heavier than each of the bags of equal

Nana76 [90]

I'm here buddy,

so, let's take the value of the two bags with equal weight as x.

= x + x + (x + $\frac{6}{5}$ ) = $\frac{27}{4}$

= 3x + $\frac{6}{5}$ = $\frac{27}{4}$

= 3x = $\frac{27}{4}$ - $\frac{6}{5}$

( let's take the LCM of 4 and 5 = 20

= 3x = $\frac{135}{20}$ - $\frac{24}{20}$

= 3x = $\frac{111}{20}$

= x = $\frac{111}{20}$ ÷ $\frac{3}{1}$ = $\frac{111}{20}$ × $\frac{1}{3}$ = $\frac{37}{20}$

So, the weight of the equal bags are $\frac{37}{20}$ and the weight of the third bag ( heavy one ) is $\frac{37}{20}$ + $\frac{6}{5}$ = $\frac{37}{20}$ + $\frac{24}{20}$ = $\frac{61}{20}$

1st bag = $\frac{37}{20}$ kg

2nd bag = $\frac{37}{20}$ kg

3rd bag = $\frac{61}{20}$ kg

Hope it helps...

7 0

3 years ago

What is the number three and eight tenths as a decimal.

natali 33 [55]

Answer:

3.8

Step-by-step explanation:

3 8/10 can be written as 3.xx because all we have to do is 8 divided by 10 which equals .8 so 3+.8=3.8

7 0

3 years ago