Question

Find the six first terms of an arithmetic sequence with: d = 2 Po= 30

Answer 1

Answer:

The first six terms of this arithmetic sequence are: 30, 32, 34, 36, 38, 40

Step-by-step explanation:

The nth term of an arithmetic sequence is given by:

$P_n = P_0 + nd$

In which d is the common difference, that is, each term is increased by d.

d = 2, Po= 30

First term is 30, each consecutive is increased by 2. So

30, 32, 34, 36, 38, 40