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Likurg_2 [28]
3 years ago
12

35 points | Hi, could I have some help? :)

Mathematics
1 answer:
pantera1 [17]3 years ago
8 0
For the first equation, you start at 0 and go by 30. The second one you start at 125 then go up gradually by 20 like you did for the first equation. Hope it helped
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Find 6 tenths of 80cm
Rzqust [24]

Answer:

6/10 of 80 is 48

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3 years ago
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I NEED HELP PLEASE, THANKS.
saveliy_v [14]

Answer:

B. 33.7 mm; 54mm^2

Step-by-step explanation:

<em><u>To find the perimeter, use the formula:</u></em>

P = a + b + c

P = 12 + 12 + 9.7

P = 33.7

<em><u>To find area, use the formula:</u></em>

A = \frac{1}{2} bh

A = \frac{1}{2} (12)(9)

A = \frac{1}{2} (108)

A = 54

6 0
3 years ago
What is the area of an isosceles trapezoid, if its shorter base has length of 18 cm, the length of the altitude is 9 cm, and the
padilas [110]

The formula for the area of a triangle of base b and altitude h is A = (1/2)(b)(h).

Here, b = 18 cm and h = 9 cm.  Thus, the desired area is:

        (18 cm)(9 cm)

A = ----------------------- = 81 cm^2

                  2

This problem gives you more info than is needed to solve it.  The area of the given triangle is 81 cm^2.

5 0
4 years ago
Determine the product.
Andrei [34K]

The final expression in standard form will be 1.601 * 10^9

<h3>Indices and expoenets</h3>

Given the expression as shown:

800.5 * (2*10^6)

This can be further simplified as:

=  8.005 * 10 ^2 * 2 * 10^6\\= 16.01 * 10^{2+6}\\= 16.01 * 10^8

The final expression in standard form will be 1.601 * 10^9

Learn more on indices here: brainly.com/question/10339517

3 0
3 years ago
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Tomtit [17]

Answer:

October 30 is the day of the month she will run and walk during the same day.

Step-by-step explanation:

To determine what day of the month will she run and walk during the same day, we will list the days she plans to go running and the days she plans to walk.

From the question,  Lisa plan to go running every fifth day and walk every sixth day, then

If she begins on October 1, the days she will run will be

October 5, October 10, October 15, October 20, October 25, and October 30;

while the days she will walk will be

October 6, October 12, October 18, October 24, and October 30.

Since October 30 occurred among the days she will run and walk, then October 30 is the day of the month she will run and walk during the same day.

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