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gizmo_the_mogwai [7]
3 years ago
8

One side of the square below measures 20cm what is the approximate area of the shaded region of the square?

Mathematics
1 answer:
NNADVOKAT [17]3 years ago
8 0

Answer:

86

Step-by-step explanation:

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Which of the following would be the . most logical first step to solving this quadratic equation
mrs_skeptik [129]
Hello!

When solving a quadratic equation, we should begin by confirming that the right side is equal to 0. The equation above, however, contains a 2 on the right side.

Therefore, the most logical first step would be to subtract 2 from both sides, leaving the ride side equal to 0.

I hope this helps!
7 0
3 years ago
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If m(x)=x+5/x-1 and n(x)=x-3 which function has the same domain as (m•n)(x)
worty [1.4K]
Consider the functions m and n:


i) m(x)=\frac{x+5}{x-1}   for x≠1.

the domain of m is  all the real numbers except 1.


ii) n(x)=x-3 is a polynomial function, because x-3 is a linear polynomial. 

The domain of any polynomial function is all real numbers. To determine the Range of this function, let c be a value in the range:

x-3=c, then x=3+c.

so if we want the function to produce c, we just set x=3+c, check:

n(3+c)=(3+c)-3=c.

This means that the Range of n is all real numbers.


What this means, is that the input (x) of the function n(x) can be any real number, and the output (n(x)) can also be any number.

so let n(x)=a, consider m(a):

m(a)=(a+5)/(a-1), clearly a≠1, this means n(x)=x-3≠1, that is x≠-4
 

This means that the domain of the composed function, m(n(x)) =  say f(x), 

is all Real numbers except 4.


Check: letting x be 4, would mean n(4)=4-3=1

which would mean m(n(4))=m(1)=(1+5)/(1-1)=6/0, which makes no sense.


Answer: Any function with domain R-{4}, has the same domain of (mon)(x) 

6 0
3 years ago
The drawing below (not to scale) shows a running track. The ends are semicircles. The distance between the two inner parallel st
aleksklad [387]
We are looking for the inner perimeter of the track. Since there are two semicircles, these mix to form one full circle so we can use the formula to find the circumference of the circle with a diameter of 60 m, which was given to us. With a diameter of 60m, the radius will be 30m. Now we can solve this problem.
C = 2πr
C = 2π(30)
C = 60π
The semicircle ends of the track are a distance of 60π m, and now we just need to add the lengths of the inner track which are 100 m each. So:
P = 60π + 100m + 100m
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4 0
3 years ago
One case can hold 3 boxes.Each box can hold 3 binders.How man cases are needed to hold 126 binders?
stealth61 [152]
14 because 126 ÷3=42 and 42÷3 =14

7 0
3 years ago
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X^2 + x - 56 = 0<br> Solve for x
NISA [10]

Answer: x = 7 or x = -8

x² + x - 56 = 0

⇔ x² + 8x - 7x - 56 = 0

⇔ x(x + 8) - 7(x + 8) = 0

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or x + 8 = 0

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Step-by-step explanation:

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