<em>Answer: 52</em>
<em />
<em>Step-by-step explanation:</em>
<em>8x6+(12-4)÷2</em>
<em>Parenthesis' first</em>
<em>8x6+8÷2</em>
<em>multiplication next</em>
<em>48+8÷2</em>
<em>Division next</em>
<em>48+4</em>
<em>52</em>
Y = -0.01x^2 + 0.5x + 3
when the height y = 8
-0.01x^2 + 0.5x + 3 = 8
-0.01x^2 + 0.5x - 5 = 0
x = 13.82 and x = 36.18 so the ball is at least 8 ft high from 13.82 and 36.18 feet inclusive.- from the player.
If the player is 30 ft from the net then the ball is likely to go over the net.
Answer:
My answer was deleted but it was between 4 and 6 weeks
Step-by-step explanation:
We can see values of angles in degrees first
= 150°
Similarly
= 300°
Now reference angle means positive acute angle they will have
As we can see in attachment 150° lies in second quadrant so its reference angle will be 180°-150° = 30° from x axis line as shown.
Where as angle 300° lies in fourth quadrant so its reference angle will be 360° - 300° = 60° from x axis as shown. So clearly both reference angles are different . So 1st choice " angles donot have same reference angle" best explains it
Choice (2) and (3) are incorrect as tan is positive only in first and third quadrants and angle 300° is in fourth quadrant.
since angle 150° is in second quadrant and 300° is in fourth quadrant so both will have same negative sign so choice (4) is not correct.
So final ansewr is choice (1) "the angles donot have same reference angle"
Let the length be x so 4x+7x=10x=42 as it is the perimeter.
so 21x =42 x=2
lengths are 8 cms , 14 cms and 20 cms