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3 years ago

The local newspaper has published the passage below.

Chemistry

2 answers:

Artemon [7]3 years ago

5 0

Answer:

Solar winds do not reach well beyond our planet

Explanation:

I hope this helps :)

Rzqust [24]3 years ago

4 0

Solar winds do not reach well beyond our planet.because Traces of solar wind reach well beyond Earth and have been detected as far as Saturn. says that

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Why did the rock collector like his collection of metamorphic rocks so much?

sdas [7]

Explanation:

ABC looks like the metamorphic rocks are more usable than other rocks

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3 years ago

What observations can be made with electron microscopes that could be made before?

Alex777 [14]

<span>Electron microscopes can magnify objects to 10,000,000x the smallest object that can be viewed is larger than an electron. Electron microscopes can improve the resolution that is achieved by light microscopes. Entire cells can be viewed and their components.</span>

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3 years ago

What is the wavelength in picometers for an electron with 360 eV of kinetic energy?

Rom4ik [11]

Answer:

Wavelength = 64.635 pm

Explanation:

The expression for the deBroglie wavelength and kinetic energy is:

$\lambda=\frac {h}{\sqrt{2\times m\times K.E.}}$

Where,

$\lambda$ is the deBroglie wavelength

h is Plank's constant having value $6.626\times 10^{-34}\ Js$

m is the mass of electron having value $9.11\times 10^{-31}\ kg$

K.E. is the kinetic energy of the electron.

Given, K.E. = 360 eV

Energy in eV can be converted to energy in J as:

1 eV = 1.6022 × 10⁻¹⁹ J

So, K.E. = $360\times 1.6022\times 10^{-19}\ J=5.76792\times 10^{-17}\ J$

Applying in the equation as:

$\lambda=\frac {h}{\sqrt{2\times m\times K.E.}}$

$\lambda=\frac{6.626\times 10^{-34}}{\sqrt {{2\times 9.11\times 10^{-31}\times 5.76792\times 10^{-17}}}}\ m$

$\lambda=\frac{10^{-34}\times \:6.626}{\sqrt{10^{-48}\times \:105.0915024}}\ m$

$\lambda=6.4635\times 10^{-11}\ m$

Also, 1 m = 10¹² pm

<u>So, Wavelength = 64.635 pm</u>

4 0

4 years ago

Which of the statements below about an acid-base buffer solution is/are true?

diamong [38]

Answer:

C. II, III, IV, and V.

Explanation:

Acid buffer is generally formed by the combination of a weak acid as well as the salt of the conjugate base.

Basic buffer is formed the combination of a weak base and also the salt of the conjugate acid.

On dilution the ration of the concentration terms of the salt and weak acid/base does not change. Hence the pH of the buffer solution does not change.

When acid or base is added to buffer, it resists changes in the pH.

Therefore, option (C) is correct.

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3 years ago

Since Al2O3 reacts with a base to form salt and water, it behaves as:

Alex_Xolod [135]

I believe it’s Amphoteric oxide

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3 years ago