The formula of hydrated copper(II) sulfate is CuSO4.10H2O
<h3>What is the formula of the hydrated copper (ii) sulfate salt?</h3>
The formula of the hydrated copper (ii) sulfate is determined as follows:
Mass of hydrated salt = 12.5 g
Mass of anhydrous salt = 8.0 g
Mass of water = 12.5 - 8 = 4.5 g
mole ratio of water and anhydrous salt is;
4.5/18 : 8.0/159.5
0.562 : 0.05
10 : 1
Water of crystallization (n) = 10.
Therefore, the formula of hydrated copper(II) sulfate is CuSO4.10H2O
Learn more about water of crystallization at: brainly.com/question/26146814
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Covalent compounds have a low boiling point. All the other answers apply to ionic compounds.
Mass % of NaCl = 0.9 % (m/v)
Density of 0.9 % NaCl is about 1.0 g/mL
Volume of NaCl in mL :
= 11.25 mL NaCl
Answer:
Sample A is a pure substance
Sample B is a mixture
Explanation:
We are told that the when the yellow solid, sample A is ground it turned to orange colour and was then dissolved. Some part of the solid settled out at the bottom of the beaker while some part floated on top of the water. 50g of the solid was dissolved and 50.1g of the solid was recovered.
This implies that the substance is pure since the mass dissolved was almost the same mass recovered. The 0.1g addition in mass may result from incomplete drying of the solid.
For sample B, the distillation of the sample of density 0.77 g/ml left a fraction in the beaker with density 1.04 g/ml indicating that the substance is a mixture. Different components of a mixture possess different densities.
