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3 years ago

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A 01.0kg baseball is hit through a neighbors window.just before it hits the window,the ball has a kinetic energy of 200j.what wa

s the balls velocity just before it hit the window?

1 answer:

dangina [55]3 years ago

5 0

Nothing
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dusya [7]

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3 years ago

I WILL GIVE BRAINLIST IF YOU DO THIS

LuckyWell [14K]

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3.When the forward forces are bigger than the opposing forces, you speed up (accelerate). As you go faster, the force of air resistance pushing back on you increases. Eventually, the forces become balanced (the forward forces are the same size as the opposing forces). Once the forces become balanced, your speed stays the same.

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3 years ago

How many atoms is 9.8 moles of calcium

IrinaK [193]

Answer:

0.24

Explanation:

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3 years ago

Read 2 more answers

3) a) (2 points) Label the 1H NMR spectrum of adipic acid by identifying key resonances. Use letters (a, b, c, etc.) to match Hs

Bess [88]

Answer:

The label of spectrum is attached.

Explanation:

adipic acid is equal to:

COOH - CH2 - CH2 - CH2 - CH2 - COOH

(1) (2) (3) (3) (2) (1)

The structure of adipic acid indicates that it has 3 equivalent carbons, therefore it should have 3 peaks in the spectrum:

The first peak at approximately 172 ppm is from carbon (1) COOH. The second peak is at approximately 23 ppm and is by carbon number (3) CH2. and the third peak is at approximately 37 ppm and is due to group number (2) CH2.

3 0

3 years ago

Consider the insoluble compound silver bromide , AgBr . The silver ion also forms a complex with ammonia . Write a balanced net

Degger [83]

Answer:

- $AgBr(s)+2NH_3(aq)\rightleftharpoons Ag(NH_3)_2^+(aq)+Br^-(aq)$

- $K=1.2x10^{-5}$

Explanation:

Hello,

In this case, by considering the dissolution of silver bromide:

$AgBr(s)\rightleftharpoons Ag^+(aq)+Br^-(aq) \ \ \ Ksp=[Ag^+][Br^-]=7.7x10^{-13}$

And the formation of the complex:

$Ag^+(aq)+2NH_3(aq)\rightleftharpoons Ag(NH_3)_2^+(aq)\ \ \ Kf=\frac{[Ag(NH_3)_2^+]}{[Ag^+][NH_3]^2}=1.6x10^7$

We obtain the balanced net ionic equation by adding the aforementioned equations:

$AgBr(s)+Ag^+(aq)+2NH_3(aq)\rightleftharpoons Ag(NH_3)_2^+(aq)+Br^-(aq)+Ag^+(aq)\\\\AgBr(s)+2NH_3(aq)\rightleftharpoons Ag(NH_3)_2^+(aq)+Br^-(aq)$

Now, the equilibrium constant is obtained by writing the law of mass action for the non-simplified net ionic equation:

$AgBr(s)+Ag^+(aq)+2NH_3(aq)\rightleftharpoons Ag(NH_3)_2^+(aq)+Br^-+Ag^+\\\\K=[Ag^+][Br^-]*\frac{[Ag(NH_3)_2^+]}{[Ag^+][NH_3]^2}$

So we notice that the equilibrium constant contains the solubility constant and formation constant for the initial reactions:

$K=Ksp*Kf=7.7x10^{-13}*1.6x10^{7}\\\\K=1.2x10^{-5}$

Best regards.

4 0

3 years ago