Ask question

Ask question

All categories

3 years ago

13

A 01.0kg baseball is hit through a neighbors window.just before it hits the window,the ball has a kinetic energy of 200j.what wa

s the balls velocity just before it hit the window?

1 answer:

dangina [55]3 years ago

5 0

Nothing
ujyfjgxyvctxjgxj

You might be interested in

when 57.0 g copper are reacted with silver nitrate solution, 138g of silver are obtained. what is the percent yield of silver ob

maks197457 [2]

Answer:

86.96

Explanation:

5 0

2 years ago

A compound with molecular formula C4H8O2, shows absorptions at 2500-3300 cm-1 (broad), 1720 cm-1 and at 1200 cm-1 on the IR spec

xxMikexx [17]

Answer:

Butanoic Acid:

I have attached the structure of Butanoic Acid. Please refer to the attachment.

Explanation:

Solution:

First of all, we need to calculate the double bond equivalent (DBE) for the compound given:

Compound = C4H8O2

DBE = (C +1) - (H + X - N)/2

C = no. of carbons

H = no. of Hydrogen

X = no. of Halogens

N = no. of Nitrogen

DBE = (4+1) - (8/2)

DBE = 5-4

DBE = 1

It indicates the presence of 1 double bond in the possible structure.

Further structure can be identified by looking the peak values of the spectrum. So, we have,

2500 - 3300 = it indicates the presence of -COOH group

1720 = it indicates the (C=0) stretching

1200 = It indicates the (C-O) stretching

SO, the possible structure is

Butanoic Acid:

I have attached the structure of Butanoic Acid. Please refer to the attachment.

7 0

3 years ago

What is the energy of light associated with a transition from n=3 to n=8 in a hydrogen atom? Does this represent absorption or e

solong [7]

Explanation:

Energy levels to be n = 8 and n = 3. Rydberg's equation will allow you calculate the wavelength of the photon emitted by the electron during this transition

1λ = R ⋅ (1/nf^2 − 1/ni^2)

where,

λ - the wavelength of the emitted photon

R - Rydberg's constant = 1.0974 x 10^7m

nf - the final energy = 8

ni - the initial energy level = 3

1/λ = 1.0974 x 10^7 * (1/8^2 − 1/3^2)

= -1.05x 10^6 m.

Using Heinsberg's equation,

E = (h * c)/λ

Calculating the energy of this transition you'll have to multiply Rydberg's equation by h * c

where,

h - Planck's constant = 6.626 x 10^−34 Js

c - the speed of light = 3.0 x 10^8 m/s

So, the transition energy, E = (6.626 x 10^−34 * 3 x 10^8) * -1.05x 10^6

= -2.08 x 10^-19 J.

B.

When an electron transitions from a less excited state to a excited state (higher energy orbit), the difference in energy is absorbed as a photon.

The energy is negative which means energy is lost or dissipated to the surroundings. Therefore, an absorption of photons.

8 0

3 years ago

Compare an oxygen particle to a water particle. In your answer , include describing how they are different and similar.

Naddik [55]

Answer:

An oxygen molecule consists of two oxygen (o2) atoms bound together and a water molecule consists of two hydrogen atoms and one oxygen atom (h20). H20 has a higher evaporation temperature than oxygen therefore it stays a liquid at room temperature unlike oxygen. Both have oxygen atoms.

5 0

3 years ago

How many Joules of heat will be given off by 55.0g of water as it cools from 87.3°C to 25.0°C?

PSYCHO15rus [73]

Answer:

Q = -14322.77 J

Explanation:

Given data:

Mass of water = 55.0 g

Initial temperature = 87.3°C

Final temperature = 25.0 °C

Heat given off = ?

Solution:

Specific heat capacity:

It is the amount of heat required to raise the temperature of one gram of substance by one degree.

Specific heat capacity of water is 4.18 J/g.°C

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT = 25.0 °C - 87.3°C

ΔT = - 62.3 °C

Q = 55.0 g×4.18 J/g.°C × - 62.3 °C

Q = -14322.77 J

5 0

3 years ago