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White raven [17]
3 years ago
11

Find the value of the expression: p^2q^2+pq–q^3–p^3 for p=1 and q=−1

Mathematics
1 answer:
Basile [38]3 years ago
4 0

Answer:

0

Step-by-step explanation:

(1)^2(-1)^2 +(1)(-1) -(-1)^3 -(1)^3

 = 1·1 -1 -(-1) -1

 = 1 - 1 + 1 - 1 = 0

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soldi70 [24.7K]

Answer:

\displaystyle m\angle AED=32.5^\circ

Step-by-step explanation:

<u>Angles in a Circle</u>

An exterior angle of a circle is an angle whose vertex is outside a circle and the sides of the angle are secants or tangents of the circle.

Segments AE and DE are secants of the given circle. They form an exterior angle called AED.

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\displaystyle m\angle AED=32.5^\circ

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