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2 years ago

Help me pliss which one is correct?

Mathematics

2 answers:

navik [9.2K]2 years ago

5 0

The answer to your question is D (2,5)

Anna71 [15]2 years ago

4 0

D. (2,5) is the answer

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How to find matrics M

makkiz [27]

$\left[\begin{array}{ccc}9&7\\-4&2\end{array}\right] -4M=\left[\begin{array}{ccc}-3&3\\4&-18\end{array}\right]\qquad(*) \\\\M=\left[\begin{array}{ccc}a&b\\c&d\end{array}\right]\to4M=\left[\begin{array}{ccc}4a&4b\\4c&4d\end{array}\right]$

$(*)\qquad\left[\begin{array}{ccc}9&7\\-4&2\end{array}\right] -\left[\begin{array}{ccc}4a&4b\\4c&4d\end{array}\right]=\left[\begin{array}{ccc}-3&3\\4&-18\end{array}\right]\\\\\left[\begin{array}{ccc}9-4a&7-4b\\-4-4c&2-4d\end{array}\right]=\left[\begin{array}{ccc}-3&3\\4&-18\end{array}\right]\\.\qquad\qquad\qquad\qquad\ \ \ \Downarrow\\(_{11})\qquad9-4a=-3\ \ \ |-9\\-4a=-12\ \ \ \ |:(-4)\\a=3\\\\(_{12})\qquad7-4b=3\ \ \ \ |-7\\-4b=-4\ \ \ \ |:(-4)\\b=1$

$(_{21})\qquad-4-4c=4\ \ \ \ |+4\\-4c=8\ \ \ \ |:(-4)\\c=-2\\\\(_{22})\qquad2-4d=-18\ \ \ \ |-2\\-4d=-20\ \ \ \ \ |:(-4)\\d=5\\\\Answer:\ A.\ M=\left[\begin{array}{ccc}3&1\\-2&5\end{array}\right]$

3 0

3 years ago

PLEASE HELP ASAP!!!!! <br><br>Which function could be shown in the graph below?<br>

Leokris [45]

Answer:

The answer is A

Step-by-step explanation:

I draw a graph

5 0

3 years ago

Over 25.5 days, a pond's water level changed by an average of −0.32 centimeter each day. What was the total change in the water

Marianna [84]

8.16 cm is the total change in water level.

3 0

3 years ago

Read 2 more answers

Evaluate h(5t^{2})given that h(t)=17-11t

Gala2k [10]

$h(t)=17-11t$
$h(5t^{2})=17-11(5t^{2})$
$h(5t^{2})=17-55t^{2}$

5 0

3 years ago

TRIGONOMETRY , can you solve this plz:(<br>even if you know one of them,plz help:)

daser333 [38]

Answer:

See below

Step-by-step explanation:

$\frac{1}{1-cos A} - \frac{1}{1+cos A} =2 cosec A cot A \\ \\ L. H. S.= \frac{1}{1-cos A} - \frac{1}{1+cos A} \\ \\ = \frac{1+cos A - (1 - cos A)}{(1-cos A)(1+cos A)}\\ \\ = \frac{1+cos A - 1 + cos A}{1-cos^{2} A}\\ \\ = \frac{2cos A }{sin^{2} A}\\ \\ =2 .\frac{1}{sin A}.\frac{cos A }{sin A}.\\ \\ = 2.cosec \: A.cot \: A \\ \\ = R.H.S$

5 0

2 years ago

Help me pliss which one is correct?​

Help me pliss which one is correct?