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3 years ago

Solve for w. Show your work. ( 36 ÷ 3 )( 2 x 6 ) = w

Mathematics

2 answers:

LenaWriter [7]3 years ago

7 0

W = 144. Evaluate the equations inside the parentheses. Which is 12 x 12 then evaluate that. Which equals, 144.

disa [49]3 years ago

5 0

Answer: 144

Step-by-step explanation:

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Ray UW is the angle bisector of AngleVUT.

tester [92]

Answer:

AngleWUT =38°, option 2

Step-by-step explanation:

We have three rays passing through U. A ray is set extend in one direction with one fixed point.

We have UW ray bisecting VUT.As the ray bisects the angle between VUW and WUT would be same .

Given angles are (4x+6)° and (6x-10)°.

As these angles are equal

$4x+6=6x-10$

$2x=16$

$x=8$

AngleWUT = (6x – 10)°

and x is 8 so on substituting AngleWUT =38°.

5 0

4 years ago

Read 2 more answers

What is the value of X?

PIT_PIT [208]

Answer:

The last choice: x = 3.

Step-by-step explanation:

M < WYX = 1/2 * 78 = 39 degrees ( angle opposite te arc of 78 degrees).

Therefore m < XWY = 180-114-39 = 27 degrees.

7x + 6 = 27

7x = 21

x = 3.

3 0

3 years ago

A ball is thrown into the air from a height of 4 feet at time t = 0. The function that models this situation is h(t) = -16t2 + 6

katrin2010 [14]

Answer:

Part a) The height of the ball after 3 seconds is $49\ ft$

Part b) The maximum height is 66 ft

Part c) The ball hit the ground for t=4 sec

Part d) The domain of the function that makes sense is the interval

[0,4]

Step-by-step explanation:

we have

$h(t)=-16t^{2} +63t+4$

Part a) What is the height of the ball after 3 seconds?

For t=3 sec

Substitute in the function and solve for h

$h(3)=-16(3)^{2} +63(3)+4=49\ ft$

Part b) What is the maximum height of the ball? Round to the nearest foot.

we know that

The maximum height of the ball is the vertex of the quadratic equation

Convert the function into a vertex form

$h(t)=-16t^{2} +63t+4$

Group terms that contain the same variable, and move the constant to the opposite side of the equation

$h(t)-4=-16t^{2} +63t$

Factor the leading coefficient

$h(t)-4=-16(t^{2} -(63/16)t)$

Complete the square. Remember to balance the equation by adding the same constants to each side

$h(t)-4-16(63/32)^{2}=-16(t^{2} -(63/16)t+(63/32)^{2})$

$h(t)-(67,600/1,024)=-16(t^{2} -(63/16)t+(63/32)^{2})$

Rewrite as perfect squares

$h(t)-(67,600/1,024)=-16(t-(63/32))^{2}$

$h(t)=-16(t-(63/32))^{2}+(67,600/1,024)$

the vertex is the point (1.97,66.02)

therefore

The maximum height is 66 ft

Part c) When will the ball hit the ground?

we know that

The ball hit the ground when h(t)=0 (the x-intercepts of the function)

$h(t)=-16t^{2} +63t+4$

For h(t)=0

$0=-16t^{2} +63t+4$

using a graphing tool

The solution is t=4 sec

see the attached figure

Part d) What domain makes sense for the function?

The domain of the function that makes sense is the interval

[0,4]

All real numbers greater than or equal to 0 seconds and less than or equal to 4 seconds

Remember that the time can not be a negative number

6 0

3 years ago

Select the best answer 7 x (-3) x (-2)^2=

vlada-n [284]

7(-3)(-2)²

-21(-2)²

-21(4)

= -84

I hope that's help !

6 0

4 years ago

What is the total cost of an item priced $4.95 if there is 5% sales tax?

Paha777 [63]

4.95+4.95×0.05=5.20
5 dollars 20 cents

7 0

4 years ago