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3 years ago

I am confused on what I need to do. someone please help?

Mathematics

1 answer:

viktelen [127]3 years ago

4 0

Answer:

x = 16

Step-by-step explanation:

Since ∆ABC is congruent to ∆DEC, their corresponding angles would be equal to each other.

<B is congruent to <E, therefore,

<B = <E

x + 15 = 6x - 65 (substitution)

Collect like terms

x - 6x = -15 - 65

-5x = -80

Divide both sides by -5

x = 16

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A radioactive material decays over time. Find k, if

Arturiano [62]

Answer is in the photo. I can only upload it to a file hosting service. link below!

tinyurl.com/wpazsebu

4 0

3 years ago

Two sisters, sister A and sister B, play SCRABBLE with each other every evening. Sister A is a statistician, and she draws a ran

snow_tiger [21]

Answer:

First question: LCL = 522, UCL = 1000.5

Second question: A sample size no smaller than 418 is needed.

Step-by-step explanation:

First question:

Lower bound:

0.36 of 1450. So

0.36*1450 = 522

Upper bound:

0.69 of 1450. So

0.69*1450 = 1000.5

LCL = 522, UCL = 1000.5

Second question:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

The margin of error is:

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

The project manager believes that p will turn out to be approximately 0.11.

This means that $\pi = 0.11$

95% confidence level

So $\alpha = 0.05$ , z is the value of Z that has a pvalue of $1 - \frac{0.05}{2} = 0.975$ , so $Z = 1.96$ .

The project manager wants to estimate the proportion to within 0.03

This means that the sample size needed is given by n, and n is found when M = 0.03. So

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

$0.03 = 1.96\sqrt{\frac{0.11*0.89}{n}}$

$0.03\sqrt{n} = 1.96\sqrt{0.11*0.89}$

$\sqrt{n} = \frac{1.96\sqrt{0.11*0.89}}{0.03}$

$(\sqrt{n})^2 = (\frac{1.96\sqrt{0.11*0.89}}{0.03})^2$

$n = 417.9$

Rounding up

A sample size no smaller than 418 is needed.

6 0

3 years ago

Whats the answer to this?

marysya [2.9K]

Answer:

$(x+2)(x+3)$

Step-by-step explanation:

Use the sum-product pattern

$x^2+5x+6$

$x^2+3x+2x+6$

Common factor from the two pairs

$x^2+3x+2x+6$

$x(x+3)+2(x+3)$

Rewrite in factored form

$x(x+3)+2(x+3)$

$(x+2)(x+3)$

4 0

3 years ago

if hayden and uri have 1250, and hayden and willow have 830, and uri has 4 times more than willow. how much does hayden have

svp [43]

Answer:

690

Step-by-step explanation:

Let

hayden have "h"

uri have "u"

and

willow have "w"

Hayden & Uri have 1250. we can write:

h + u = 1250

Hayden & Willow have 830, so we can write:

h + w = 830

Uri has 4 times than Willow, so we can write:

u = 4w

Putting 3rd equation in first, we get:

h + u = 1250

h + 4w = 1250

Now, we take 2nd and 4th equation, which are:

h + w = 830

h + 4w = 1250

Multiplying this first one with -1, gives us:

-1 * [h+w=830] = -h - w = -830

Now we add this up with 4th equation. Shown below:

- h - w = - 830

h + 4w = 1250

----------------------

4w - w = 1250 - 830

3w = 420

w = 420/3

w = 140

We know u = 4w, so u = 4 * 140 = 560

u = 560

Also, we know h + w = 830, so

h + 140 = 830

h = 830 - 140

h = 690

Thus Hayden has 690

7 0

3 years ago

2-x+1/x-2-x-4/x+2 can be written as a single fraction

8_murik_8 [283]

Answer:

2x-3/3

Step-by-step explanation:

Hope this helps

6 0

3 years ago