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dedylja [7]
3 years ago
5

A rectengular school gym has a length of 120 feet and a perimeter of 520 feet.What is the width,in feet,of theschool gym

Mathematics
1 answer:
labwork [276]3 years ago
3 0

Answer: 140 ft

Step-by-step explanation:

120+120=240

520-240= 280

280/2= 140

You might be interested in
Fill in the missing expression
padilas [110]

Answer:

The complete table is:

[ 5a ]           +    [ a + 3 ]      +    [ 4a ]     =    [ 10a + 3 ]

  +                         +                    +                    +

[ 2b ]          +     [ 4 + a ]      +     [ -a  ]     =    [  2b + 4 ]

  +                       +                     +                    +

[ 2a ]          +    [ a + 1 ]       +   [  -3a  ]    =   [     1      ]

  =                      =                     =                     =

[ 7a + 2b ]  +   [ 3a + 8 ]    +     [   0   ]    =   [10a + 2b + 8 ]

Explanation:

You can determine the content of each box by subtraction, running the rows and the columns.

The expressions are:

[ 5a ]  +    [          ]   +    [ 4a ]     =    [ 10a + 3 ]

  +                +                +                    +

[ 2b ]  +   [ 4 + a ]   +     [      ]     =    [              ]

  +              +                   +                    +

[      ]   +   [         ]   +      [  -3a  ]  =   [     1      ]

  =               =                   =                   =

[      ]  +   [ 3a + 8 ]  +  [         ]    =   [10a + 2b + 8 ]

<u>1. First row:</u>

[ 5a ]  +    [          ]   +    [ 4a ]     =    [ 10a + 3 ]

[      ] = [10a+ 3]  - [ 4a ] - [ 5a ] = 10a - 4a - 5a + 3 = a + 3

<u>2. Second colum:</u>

[ a + 3 ] + [ 4 + a ] + [       ] =  [ 3a + 8 ]

[        ] = [ 3a + 8 ] - [ a + 3 ] - [ 4 + a ] = 3a - a  + a  + 8 - 4 - 3 = a + 1

So far, you have completed this:

[ 5a ]  +    [ a + 3 ]   +    [ 4a ]     =    [ 10a + 3 ]

  +                +                +                    +

[ 2b ]  +   [ 4 + a ]   +     [      ]     =    [              ]

  +              +                   +                    +

[      ]   +   [ a + 1 ]   +     [  -3a  ]  =   [     1      ]

  =               =                   =                   =

[      ]  +   [ 3a + 8 ]  +  [         ]    =   [10a + 2b + 8 ]

<u></u>

<u>3. Complete the row 3:</u>

<u></u>

     [      ]   +   [ a + 1 ]   +      [  -3a  ]  =   [     1      ]

    [      ]   =    [     1      ]   -   [ a + 1 ]   -    [  -3a  ]  = - a + 3a + 1 - 1 = 2a

So far, you have completed this:

[ 5a ]  +    [ a + 3 ]   +    [ 4a ]     =    [ 10a + 3 ]

  +                +                +                    +

[ 2b ]  +   [ 4 + a ]   +     [      ]     =    [              ]

  +              +                   +                    +

[   2a   ]   +   [ a + 1 ]   +     [  -3a  ]  =   [     1      ]

  =               =                   =                   =

[      ]  +   [ 3a + 8 ]  +  [         ]    =   [10a + 2b + 8 ]

<u></u>

<u>4. Complete the fourth column:</u>

[ 10a + 3 ] + [    ] + [   1   ] = [10a + 2b + 8 ]

[    ] = 10a + 2b + 8 - 10a - 3 - 1 = 2b + 4

So far, this is the results:

[ 5a ]  +    [ a + 3 ]   +    [ 4a ]     =    [ 10a + 3 ]

  +                +                +                    +

[ 2b ]  +   [ 4 + a ]   +     [      ]     =    [  2b + 4 ]

  +              +                   +                    +

[   2a   ]   +   [ a + 1 ]   +     [  -3a  ]  =   [     1      ]

  =               =                   =                   =

[      ]  +   [ 3a + 8 ]  +  [         ]    =   [10a + 2b + 8 ]

<u>5. Complete the second row:</u>

[ 2b ]  +   [ 4 + a ]   +     [      ]     =    [  2b + 4 ]

 [      ]   =   [  2b + 4 ] - [ 2b ]  -   [ 4 + a ]  = 2b - 2b + 4 - 4 - a = - a

So far:

[ 5a ]  +    [ a + 3 ]      +    [ 4a ]     =    [ 10a + 3 ]

  +                +                    +                    +

[ 2b ]  +   [ 4 + a ]      +     [ -a  ]     =    [  2b + 4 ]

  +               +                     +                    +

[   2a   ]   +   [ a + 1 ]   +   [  -3a  ]  =   [     1      ]

  =               =                    =                   =

[      ]  +   [ 3a + 8 ]  +     [         ]    =   [10a + 2b + 8 ]

<u>6. Complete the first colum:</u>

[ 5a ] + [ 2b ] + [2a ] = [   ]

[   ] = [ 7a + 2b ]

So far:

[ 5a ]           +    [ a + 3 ]      +    [ 4a ]     =    [ 10a + 3 ]

  +                         +                    +                    +

[ 2b ]           +   [ 4 + a ]      +     [ -a  ]     =    [  2b + 4 ]

  +                       +                     +                    +

[ 2a ]          +   [ a + 1 ]       +   [  -3a  ]    =   [     1      ]

  =                      =                     =                    =

[ 7a + 2b ]  +   [ 3a + 8 ]   +     [         ]    =   [10a + 2b + 8 ]

<u>7. Complete the last row:</u>

[ 7a + 2b ]  +   [ 3a + 8 ]   +     [         ]    =   [10a + 2b + 8 ]

[         ]    =   [10a + 2b + 8 ] - [ 7a + 2b ] - [ 3a + 8 ] = 0

The complete table is:

[ 5a ]           +    [ a + 3 ]      +    [ 4a ]     =    [ 10a + 3 ]

  +                         +                    +                    +

[ 2b ]           +   [ 4 + a ]      +     [ -a  ]     =    [  2b + 4 ]

  +                       +                     +                    +

[ 2a ]          +   [ a + 1 ]       +     [ -3a  ]    =   [     1      ]

  =                      =                     =                     =

[ 7a + 2b ]  +   [ 3a + 8 ]    +     [   0  ]     =   [10a + 2b + 8 ]

5 0
3 years ago
What is the value of x in the equation 1.8 minus 3.7 x = negative 4.2 x + 0.3?
aniked [119]

Answer:

-3

Step-by-step explanation:

1. subtract 0.3 from both sides

2. add 3.7x to both sides

3. Divide both sides by -0.5

3 0
3 years ago
Read 2 more answers
What is a three letter word used to show division in a word problem?
olasank [31]
A three-letter word used to show division in a word problem is PER.
6 0
3 years ago
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If f (x) = x + 7 and g (x) = StartFraction 1 Over x minus 13 EndFraction, what is the domain of (f circle g) (x)?
Rashid [163]

Answer:

R-{13}

Step-by-step explanation:

We are given that

f(x)=x+7

g(x)=\frac{1}{x-13}

We have to find the domain of fog(x).

fog(x)=f(g(x))

fog(x)=f(\frac{1}{x-13})

fog(x)=\frac{1}{x-13}+7=\frac{1+7x-91}{x-13}=\frac{7x-90}{x-13}

Domain of f(x)=R

Because it is linear function.

Domain of g(x)=R-{13}

Because the g(x) is not defined at x=13

fog(x) is not defined at x=13

Therefore, domain of fog(x)=R-{13}

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Harrizon [31]
A) The area of a rectangle is A = lw, where l=length of the rectangle and w=width of the rectangle. You know the length of the gift shop, l = 20x + 24. You know the width, w = 36x - 20. Plug those expressions into the equation for area of a rectangle and multiply/foil:
A = lw\\&#10;A = (20x + 24)(36x - 20)\\&#10;A = (20x)(36x) + (20x)(-20) +  (24)(36x) + (24)(-20)\\&#10;A = 720x^{2} - 400x + 864x - 480\\&#10;A = 720x^{2} + 464x - 480

The expression for the area of the gift shop is 720x^{2} + 464x - 480.

B) The equation for the perimeter of the gift shop is P = 2(l+w), where l = length and w = width. Plug your values for l and w into this equation:
P = 2(l+w)\\&#10;P = 2(20x + 24 + 36x - 20)\\&#10;P = 2(56x + 4) = 2(56x) + 2(4)\\&#10;P = 112x + 8

The expression for the perimeter of the gift shop is 112x + 8

C) Since you know the perimeter is going to be 176 ft, that means P = 176. Plug that into the equation you found in part B, P = 112x + 8, and solve for x.
P = 112x + 8\\&#10;176 = 112x + 8\\&#10;112x =  168&#10;x = 1.5

Once you solve for x, you can plug x into your equations for width and length to find the dimensions. x = 1.5, so:
1) L<span>ength = 20x+24 feet 
</span>Length = 20(1.5) + 24 feet = 54 feet
2) Width = <span>36x-20 feet
Width = 36(1.5)-20 feet = 34 feet

Your dimensions are 54 feet (length) by 34 feet (width).
</span>
3 0
3 years ago
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