Question

Carla and Jordan were trying to solve the equation: (x+1)(x-1)=8(x+1)(x−1)=8left parenthesis, x, plus, 1, right parenthesis, left parenthesis, x, minus, 1, right parenthesis, equals, 8 Carla said, "I'll multiply (x+1)(x-1)(x+1)(x−1)left parenthesis, x, plus, 1, right parenthesis, left parenthesis, x, minus, 1, right parenthesis and rewrite the equation as x^2-1=8x 2 −1=8x, squared, minus, 1, equals, 8. Then I'll add 111 both sides and take the square root." Jordan said, "The left-hand side is factored, so I'll use the zero product property." Whose solution strategy would work?

Answer 1

Answer:

Only Carla

Step-by-step explanation:

Its the right way to solve (x+1)(x-1)=8