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choli [55]
3 years ago
6

For this question I need to find 80% of 20

Mathematics
1 answer:
Ipatiy [6.2K]3 years ago
7 0

Answer:

16

Step-by-step explanation:

.8 x 20 =16

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Simplify (x+4)^2 how is this simplified
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Is known that

(a + b)² = a² + 2.a.b + b²

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(x + 4)² = x² + 2.x.4 + 4² = x² + 8x + 16

5 0
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Maria bought seven boxes a week later half of all her boxes were destroyed in a fire there are only 22 boxes left with how many
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Step-by-step explanation:

she started off with 44 boxes

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Can you find the slope for me, please?
shusha [124]
The slope is -3/2

Use the two ordered pairs (-2,0) and (0,-3) and do y2-y1/x2-x1

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What is the volume of the prism pls help
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I would say 42 but some of the image is cut off so I may be wrong:))

Step-by-step explanation:

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2 years ago
Suppose that a jewelry store tracked the amount of emeralds they sold each week to more accurately estimate how many emeralds to
RUDIKE [14]

Answer:

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

And for this case the 95% confidence interval is given by (2.13; 2.37)

We have a point of estimate for the sample mean with this formula:

\bar X = \frac{Upper+ Lower}{2}= \frac{3.37+2.13}{2}= 2.75

And for the margin of error we have the following estimation:

ME= \frac{Upper -Lower}{2}= \frac{3.37-2.13}{2}= 0.62

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X represent the sample mean

\mu population mean (variable of interest)

s represent the sample standard deviation

n represent the sample size  

Solution to the problem

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

And for this case the 95% confidence interval is given by (2.13; 2.37)

We have a point of estimate for the sample mean with this formula:

\bar X = \frac{Upper+ Lower}{2}= \frac{3.37+2.13}{2}= 2.75

And for the margin of error we have the following estimation:

ME= \frac{Upper -Lower}{2}= \frac{3.37-2.13}{2}= 0.62

5 0
3 years ago
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