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2 years ago

Acellus

Mathematics

2 answers:

daser333 [38]2 years ago

8 0

Step-by-step explanation:

$3.375 \: {cm}^{2}$

I hope it helps

have a great day

#Captainpower

RideAnS [48]2 years ago

4 0

Answer:

<h2>Question:</h2>

Find the area of the following

parallelogram:

1.5 cm

2.25 cm

<h2>Solution:</h2>

$\huge\fbox\purple{Area = Product of the given 2 sides}\$

(1.5×2.25)cm²

Hope it helps

-------☆ﾟ.･｡ﾟᵴɒƙυᴚᴀ_ƨȶäᴎ❀

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What is the solution to -10 x w = -50?<br> A. w = 10<br> B. w = 5<br> C. w = -5<br> D. w = -10

ZanzabumX [31]

The solution to the given equation is w = -5

<h3>Solving of expression</h3>

What is an Algebraic Expression? An algebraic expression in mathematics is an expression which is made up of variables and constants, along with algebraic operations

Given the expression below as shown;

-10w = 50

Divide both sides by -10

-10w/-10 = 50/-10

w = -5

Hence the solution to the given equation is w = -5

Learn more on equation and expression here: brainly.com/question/22048677
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1 year ago

A physicist examines 25 water samples for nitrate concentration. The mean nitrate concentration for the sample data is 0.165 cc/

xz_007 [3.2K]

Answer:

The 80% confidence interval for the the population mean nitrate concentration is (0.144, 0.186).

Critical value t=1.318

Step-by-step explanation:

We have to calculate a 80% confidence interval for the mean.

The population standard deviation is not known, so we have to estimate it from the sample standard deviation and use a t-students distribution to calculate the critical value.

The sample mean is M=0.165.

The sample size is N=25.

When σ is not known, s divided by the square root of N is used as an estimate of σM:

$s_M=\dfrac{s}{\sqrt{N}}=\dfrac{0.078}{\sqrt{25}}=\dfrac{0.078}{5}=0.016$

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3 years ago

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GuDViN [60]

<u>Answer:</u>

The correct answer option is P (S∩LC) = 0.16.

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It is known that the probability if someone is a smoker is P(S)=0.29 and the probability that someone has lung cancer, given that they are also smoker is P(LC|S)=0.552.

So using the above information, we are to find the probability hat a random person is a smoker and has lung cancer P(S∩LC).

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2 years ago

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2 years ago

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Veseljchak [2.6K]

Answer:

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3 years ago