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lapo4ka [179]
3 years ago
13

X+5.5+8=5x-13.5-4x what does x equal

Mathematics
1 answer:
wariber [46]3 years ago
8 0

Answer:

There are no values of x that makes the equation true. or in other words ( no solution)

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184 cubes difference

Explanation:

First guy made a 2x2x2 (L x W x H)
L: 2 x 2 = 4 ( twice as long)
W: 2 x 3 = 6 ( three times as wide)
H: 2 x 4 = 8 ( four times as high)

New block:

4 x 6 x 8 = 192

192 - 8 = 184 cubes different
3 0
3 years ago
A monomial of the 2 degree with a leading coefficient of 3
Ilia_Sergeevich [38]

Answer:

In the procedure

Step-by-step explanation:

we know that

A polynomial which has only one term is called monomial

The degree of a monomial is defined as the sum of all the exponents of the variables

<em>Examples</em>

If the monomial has only one variable

3x² -----> is a monomial of the 2 degree with a leading coefficient of 3

If the monomial has more than one variable

3xy ----> is a monomial of the 2 degree with a leading coefficient of 3

6 0
3 years ago
Read 2 more answers
What can you conclude about parallel lines drawn in the coordinate plane?
anygoal [31]
Parallel lines are both vertical and they don’t meet.
6 0
3 years ago
Find the work done by the force Bold Upper F equals xy Bold i plus (y minus x )Bold j over the straight line from (negative 1 co
aalyn [17]

Answer:

<h2>4/3 Joules </h2>

Step-by-step explanation:

Work is said to be done when force applied to an object causes the object to move through a distance.

Work done = Force * perpendicular distance.

\int\limits^a_b {F} \, ds

Given Force F = xy i + (y-x) j and a straight line (-1, -2) to (1, 2)

First we need to get the equation of the straight line given.

Given the slope intercept form y = mx+c

m is the slope

c is the intercept

m = y₂-y₁/x₂-x₁

m = 2-(-2)/1-(-1)

m = 4/2

m = 2

To get the slope we will substtutte any f the point and the slope into the formula y = mx+c

Using the point (1,2)

2 = 2+c

c = 0

y = 2x

Substituting y = 2x into the value of the force F = xy i + (y-x) j we will have;

F = x(2x) i + (2x - x) j

Using the coordinate (1, 2) as the value of s

W = \int\limits^a_b ({2x^2 i + x j}) \, (i+2j)\\W = \int\limits^a_b ({2x^{2}+2x }) \, dx \\W = [\frac{2x^{3} }{3} +x^{2} ]\left \ x_2=1} \atop {x_1=-1}} \right.\\W = (2(1)^3/3 + 1^2) -  (2(-1)^3/3 + (-1)^2)\\W =(2/3+1) - (-2/3+1)\\W = 2/3+2/3+1-1\\W = 4/3 Joules

8 0
3 years ago
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