Answer:
475.
Step-by-step explanation:
We have been given that for a normal distribution with μ=500 and σ=100. We are asked to find the minimum score that is necessary to be in the top 60% of the distribution.
We will use z-score formula and normal distribution table to solve our given problem.
Top 60% means greater than 40%.
Let us find z-score corresponding to normal score to 40% or 0.40.
Using normal distribution table, we got a z-score of 
.
Upon substituting our given values in z-score formula, we will get:
Therefore, the minimum score necessary to be in the top 60% of the distribution is 475.
We are given with the sequence -20, -16, -12, -8. From this sequence, we can see that the arithmetic difference is +4, from -(-20 + 16). hence following the arithmetic formula of an = a1 + d *(n-1). Substituting, an = -20 + 4 *(n-1) where n is an integer
Answer:
As it ایس the correct answer is 45
78
7.90
Answer:
x > 8
x < -16
Step-by-step explanation:
2x + 10 > 26
2x + 10 - 10 > 26 - 10
2x > 16
2x/2 > 16/2
x > 8
2x + 10 < -26
2x + 10 - 10 < - 26 - 10
2x < -36
2x/2 < -36/2
x < -16
Answer:
h = -9
Step-by-step explanation:
Distribute the 2 to the parentheses:
5h + 2(11 - h) = -5
5h + 22 - 2h = -5
Add like terms:
3h + 22 = -5
3h = -27
h = -9
