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2 years ago

Based on the figure, which of the following equations is also true?

Mathematics

1 answer:

Leno4ka [110]2 years ago

4 0

Answer:

The correct answer is B.

Step-by-step explanation:

Because you know two of the angles in a triangle are 90° and 52°, you can infer that the third angle is 38°. There is a trigonometry rule that states the sine of an angle is equivalent to the cosine of 90° minus that angle, which you can apply to here. Since $Sin(52$ ° $)$ = $\frac{17}{c}$ , you know that $Cos(90$ ° $-52$ ° $)$ or $Cos(38$ ° $)$ also equals $\frac{17}{c}$ , so choice B is the correct answer.

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Karla makes paper airplanes. Today, it takes her 32 min to make 16 paper airplanes.

Pavel [41]

Answer:

48/b

Step-by-step explanation:

32÷16=2 so it takes two minutes per airplane. if she makes airplanes for 96 minutes at the same pace (2 min per airplane) then you need to divide 96 by 2 which gives you 48!

7 0

3 years ago

the function b(n)=12n represents the number of baseballs b(n) that are needed for n games how many baseballs are needed for 15 g

Natasha2012 [34]

<span>180 n is the number of games. In this case it is 15. Enter this number into the function: b(n) = 12n = 12(15) = 180. Simply put, 12 balls are needed for each game. 15 x 12 = 180</span>

8 0

3 years ago

Consider a particle moving along the x-axis where x(t) is the position of the particle at time t, x' (t) is its velocity, and x'

vodka [1.7K]

Answer:

a) $v(t) =x'(t) = \frac{dx}{dt} = 3t^2 -12t +9$

$a(t) = x''(t) = v'(t) =6t-12$

b) $0$

c) $a(t) = x''(t) = v'(t) =6t-12$

When the acceleration is 0 we have:

$6t-12=0, t =2$

And if we replace t=2 in the velocity function we got:

$v(t) = 3(2)^2 -12(2) +9=-3$

Step-by-step explanation:

For this case we have defined the following function for the position of the particle:

$x(t) = t^3 -6t^2 +9t -5 , 0\leq t\leq 10$

Part a

From definition we know that the velocity is the first derivate of the position respect to time and the accelerations is the second derivate of the position respect the time so we have this:

$v(t) =x'(t) = \frac{dx}{dt} = 3t^2 -12t +9$

$a(t) = x''(t) = v'(t) =6t-12$

Part b

For this case we need to analyze the velocity function and where is increasing. The velocity function is given by:

$v(t) = 3t^2 -12t +9$

We can factorize this function as $v(t)= 3 (t^2- 4t +3)=3(t-3)(t-1)$

So from this we can see that we have two values where the function is equal to 0, t=3 and t=1, since our original interval is $0\leq t\leq 10$ we need to analyze the following intervals: