Answer:
a) 47.55
b) 58
c) 47.88
Step-by-step explanation:
Given that the size of the orders is uniformly distributed over the interval
$25 ( a ) to $80 ( b )
<u>a) Determine the value for the first order size generated based on 0.41</u>
parameter for normal distribution is given as ; a = 25, b = 80
size/value of order = a + random number ( b - a )
= 25 + 0.41 ( 80 - 25 )
= 47.55
<u>b) Value of the last order generated based on random number (0.6)</u>
= a + random number ( b - a )
= 25 + 0.6 ( 80 - 25 )
= 25 + 33 = 58
<u>c) Average order size </u>
= ∑ order 1 + order 2 + ----- + order 10 ) / 10
= (47.55 + ...... + 58 ) / 10
= 478.8 / 10 = 47.88
Answer:
y -3 = (-1/2)(x - 5)
Step-by-step explanation:
Slope of line: Notice that if we go from 7 to 5, the 'run' is -2 and the corresponding 'rise' from 2 to 3 is 1. Thus, the slope is m = -1/2.
Using m = -1/2 and the point (5, 3), we write the equation of this line in point-slope form as:
y -3 = (-1/2)(x - 5)
Answer:
10
Step-by-step explanation:
712.9 / 10 = 71.29
The answer is a.
I hope this helped
Answer: He sold 10 pounds of cashews .
Step-by-step explanation:
Since we have given that
Selling price of walnuts = $4.00 a pound
Selling price of cashews = $7.00 a pound
Number of pounds of walnuts = 10
Let number of pounds of cashew be x
Total price at which he sold a mixture = $5.50
According to question,

Hence, he sold 10 pounds of cashews .