Answer:
68.11% probability that the firm involved is firm B
Step-by-step explanation:
Bayes Theorem:
Two events, A and B.

In which P(B|A) is the probability of B happening when A has happened and P(A|B) is the probability of A happening when B has happened.
In this question:
Event A: Cost overrun
Event B: Agency B used.
A certain federal agency employs three consulting firms (A, B and C) with probabilities 0.40, 0.45 and 0.15.
This means that 
From past experiences, it is known that the probability of cost overruns for the firms are 0.01, 0.14, and 0.17, respectively.
This means that 
Probability of cost overrun.
Firm A is used 40% of the time, with 1% of these having cost overrun. B is used 45%, with 14% of these having cost overruns. C is used 15% of the time, with 17% of these having cost overruns.
So

What is the probability that the firm involved is firm B

68.11% probability that the firm involved is firm B
6975757441x^8 / 256
This is the answer hope this helps
Let thw second integer be x
then the first = 2x
and the third integer is = 6+x
their sum = 74
x+2x+6+x = 74
4x +6 = 74
4x = 74-6 =68
x =68÷4
x = 17
then the first integer is 2×17 = 34
the third integer is 17+6 = 23
the integers are 17 , 23 and 34
Answer:
i can Lol if you will help me after i help you
Step-by-step explanation:
put -6.5 in between -6 and -7. put -8.5 between -8 and -9. -6.5 is > than -8.5. hope this helped and i hope im right.