1 year ago

FIND THE PERIMETER OF POLYON B. -GEOMETRY

1 answer:

7 0

Please refer to the picture.

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zhannawk [14.2K]

7/g This is the correct answer to your problem

3 0

3 years ago

tiny-mole [99]

Answer:

Step-by-step explanation:

4 0

3 years ago

Alexxandr [17]

I would but my teacher has a ad blocker on and I cant access the attachment :P

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3 years ago

Bad White [126]

Looks like you have most of the details already, but you're missing one crucial piece.

$\sigma$ is parameterized by

$\vec r(u,v)=\langle u\cos3v,u\sin3v,v\rangle$

for $0\le u\le7$ and $0\le v\le\frac{2\pi}3$ , and a normal vector to this surface is

$\dfrac{\partial\vec r}{\partial u}\times\dfrac{\partial\vec r}{\partial v}=\left\langle\sin3v,-\cos3v,3u\right\rangle$

with norm

$\left\|\dfrac{\partial\vec r}{\partial u}\times\dfrac{\partial\vec r}{\partial v}\right\|=\sqrt{\sin^23v+(-\cos3v)^2+(3u)^2}=\sqrt{9u^2+1}$

So the integral of $f(x,y,z)=x^2+y^2+z^2$ is

$\displaystyle\iint_\sigma f(x,y,z)\,\mathrm dA=\boxed{\int_0^{2\pi/3}\int_0^7(u^2+v^2)\sqrt{9u^2+1}\,\mathrm du\,\mathrm dv}$

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3 years ago

Trava [24]

<span>Problem 1: 2x > 4x - 6
2x < 6
x < 3

problem 2: -3r < 10 - r
-2r < 10
r > -5

problem 3: 5c - 4 > 8c + 2
3c < -6
c < -2</span>

8 0

3 years ago