7*6*x^-8*x^3
42x^-8+3 (bases same powers add)
42x^-5
1/42x^5
<span>so the simplified </span>form<span> of 7x^-8*6x^3 is=1/42x^5</span>
To solve this, you need to isolate/get the variable "x" by itself in the inequality:
2(1 - x) > 2x Divide 2 on both sides

1 - x > x Add x on both sides to get "x" on one side of the inequality
1 - x + x > x + x
1 > 2x Divide 2 on both sides to get "x" by itself
or
(x is any number less than 1/2)
[Another way you could've solved it]
2(1 - x) > 2x Distribute 2 into (1 - x)
(2)1 + (2)(-x) > 2x
2 - 2x > 2x Add 2x on both sides
2 - 2x + 2x > 2x + 2x
2 > 4x Divide 4 on both sides to get "x" by itself


Answer:
Step-by-step explanation:
By inscribed angle theorem:
Again by inscribed angle theorem:

Step-by-step explanation:
14÷2=7
18÷2=9
for the first equation
14/y=7
cross multiply will be
7y=14
divide both sides by the co efficient of y which is 7
y=14÷2
y=2
same step for the second equation