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allsm [11]
3 years ago
12

How many triangles can be drawn with side lengths of 3 inches, 5 inches, and 6 inches???

Mathematics
1 answer:
storchak [24]3 years ago
5 0

Answer:

4 congruent triangles

Step-by-step explanation:

since there is no one of the sum of two sides is less then the third side, so it's possible to form a triangle

Use straightedge and compass, it can draw 4 triangles at a common base

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3 years ago
The measure of one angle of an octagon is two times smaller that of the other seven angles. What is the measure of each angle?
Anestetic [448]

Answer:

7 of the angles measure 144 degrees each and one angle measures 72 degrees

Step-by-step explanation:

Let

x -----> represent the measures of the seven same-size angles,

x/2 ----> represent the measure of the one that is "two times smaller."

we know that

The sum of internal angles of a polygon can be calculated as:

S=180^o(n-2)

where

n is the number of sides of the polygon

In this case

n=8 (octagon)

substitute

S=180^o(8-2)=1,080^o

so

The linear equation that represent this problem is

\frac{x}{2}+7x=1,080

solve for x

\frac{15x}{2}=1,080\\\\15x=2,160\\\\x=144^o

so

\frac{x}{2}=72^o

therefore

7 of the angles measure 144 degrees each and one angle measures 72 degrees

7 0
3 years ago
8(3a+5)???? please help!!!!!! ASAP!!!!
r-ruslan [8.4K]

I'm assuming your teacher wants you to distribute. If so, then you multiply the outer term 8 by each term inside (3a and 5). After that you add.

8 times 3a = 24a

8 times 5 = 40

So 8(3a+5) becomes 24a+40

We do not combine 24a and 40 as they are not like terms. So we leave 24a+40 as it is.

3 0
3 years ago
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