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Papessa [141]
3 years ago
13

3(2b-4a+3c) if a =1/2,b=3, and c=-2/3

Mathematics
2 answers:
valentina_108 [34]3 years ago
8 0
This is just substitution. so 3(2(3)-4(1/2)+3(-2/3)= 3(6-2-2)= 3(2) = 6. Basically you plug in the values they gave you for the variables and then just solve one step at a time
STatiana [176]3 years ago
4 0
<span>3(2(3)-4(1/2)+3(-2/3)= 3(6-2-2)= 3(2) = 6. </span>
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Solving for matrices
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D

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\left(\begin{array}{ccccc} 3&-4&-5&|&-27\\0&-26&-19&|&-168\\5&-4&4&|&-7\end{array}\right)

Subtract the third row from the second:

\left(\begin{array}{ccccc} 3&-4&-5&|&-27\\0&-26&-19&|&-168\\0&6&-6&|&18\end{array}\right)

Divide the third row by 6:

\left(\begin{array}{ccccc} 3&-4&-5&|&-27\\0&-26&-19&|&-168\\0&1&-1&|&3\end{array}\right)

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\left(\begin{array}{ccccc} 3&-4&-5&|&-27\\0&-26&-19&|&-168\\0&0&-45&|&-90\end{array}\right)

You get the system of three equations:

\left\{\begin{array}{r}3x-4y-5z=-27\\-26y-19z=-168\\-45z=-90\end{array}\right.

From the third equation

z=\dfrac{90}{45}=2.

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The solution is (1,5,2)

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3 years ago
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