Find the consistent pattern in the list of values below. 1) 4, 14.5, 25, 35.5

What is the mode for the set of values? 5 9 1 2 7 3 1 8 8 1 3

KiRa [710]

The mode is the number repeated most often, so if we arrange these numbers in order, we can see what numbers repeat the most-

1 1 1 2 3 3 5 7 8 8 9

The number that repeats the most is 1

(1 counted 3 times)

(3 counted twice)

(8 counted twice)

6 0

3 years ago

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6 4/9 + 14 2/3= 5 1/4 – 3 3/5 =

dimulka [17.4K]

Refer to the attachments!!~

8 0

2 years ago

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Hcf of two numbers is 2 and lcm is 54 if one of the number is 27 find the other number

anyanavicka [17]

Answer:

4

Step-by-step explanation:

Given that:

Let the two numbers = a and b

H. C. F of the two numbers = 2

L.C.M of the two numbers = 54

If a = 27 ; b =?

The product of a and b = product of their L. C. M and H. C. F ;

HENCE ;

27 * b = 2 * 54

27b = 108

b = 108/27

b = 4

Hence, second number is 4

7 0

3 years ago

Please help! Given the function problem

dedylja [7]

Answer:

B

Step-by-step explanation:

So we have the function:

$f(x)=\frac{9}{5}x+32$

To find the inverse, flip f(x) and x, change f(x) to f⁻¹(x), and solve for it. Thus:

$x=\frac{9}{5}f^{-1}(x)+32$

Subtract 32 from both sides:

$x-32=\frac{9}{5}f^{-1}(x)$

Multiply both sides by 5/9. The right side will cancel. Thus:

$f^{-1}(x)=\frac{5}{9}(x-32)$

Our answer is B.

And we're done!

7 0

4 years ago

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FURTHER MATHEMATICS Use determinants to solve the systems of equation:

maw [93]

Answer:

Step-by-step explanation:

$\left\{\begin{array}{ccc}2x+1y+2z&=&13\\1x+1y-2z&=&8\\1x+2y+1z&=&11\\\end{array}\right.\\\\\\\Delta=\left| \begin{array}{ccc}2&1&2\\1&1&-2\\1&2&1\end{array}\right| =2*\left| \begin{array}{ccc}1&\frac{1}{2}&1\\1&1&-2\\1&2&1\end{array}\right| =2*\left| \begin{array}{ccc}1&\frac{1}{2}&1\\0&\frac{1}{2}&-3\\0&1&3\end{array}\right| =2*(\frac{3}{2}+3)=9\\\\$

$\Delta_1=\left| \begin{array}{ccc}13&1&2\\8&1&-2\\11&2&1\end{array}\right| =2*\left| \begin{array}{ccc}13&1&2\\8&1&-2\\\frac{11}{2}& 1&\frac{1}{2}\end{array}\right| =2*\left| \begin{array}{ccc}13&1&2\\-5&0&-4\\\frac{-5}{2}& 0&\frac{5}{2}\end{array}\right| \\\\=2*(-1)*(\frac{-25}{2}-\frac{20}{2}) =45\\$

$\Delta_2=\left| \begin{array}{ccc}2&13&2\\1&8&-2\\1&11&1\end{array}\right| \\\\\\=\left| \begin{array}{ccc}3&21&0\\3&30&0\\1&11&1\end{array}\right| \\\\\\=1*(90-63) =27\\$

$\Delta_3=\left| \begin{array}{ccc}2&1&13\\1&1&8\\1&2&11\end{array}\right| \\\\\\=\left| \begin{array}{ccc}0&-1&-3\\0&-1&-3\\1&2&11\end{array}\right| \\\\\\=0\\$

$\left\{\begin{array}{ccc}x=\dfrac{\Delta_1}{\Delta}=\dfrac{45}{9}=5\\\\y=\dfrac{\Delta_2}{\Delta}=\dfrac{27}{9}=3\\\\z=\dfrac{\Delta_3}{\Delta}=\dfrac{0}{9}=0\\\end{array}\right.$

8 0

3 years ago