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2 years ago

Determine the solution for x^2-3x-28=\> 0

Mathematics

1 answer:

shepuryov [24]2 years ago

6 0

Answer: x = -4 or x = 7

Step-by-step explanation:

x^2 - 3x - 28 =/>

(factor)

(x^2 + 4)(x-7) = 0

x + 4 = 0 or x - 7 = 0

(subtract -4 from 0 and 7 from 0)

x = -4 or x =7

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Rachel babysits the Michaelson’s kids on Saturdays for 4 hours and is paid $12.50 per hour. On Sundays, she babysits at the Smit

NeTakaya

Answer:

She earns $8.00 more on Sunday

Step-by-step explanation:

Saturday 12.50x4=50.00

Sunday 14.50x4=58.00

5 0

3 years ago

The yearly sales of candles decreased from 560 to 476. By what percentage did the candle sales decrease?

Korvikt [17]

The candle sales decreases to - 15 percentage.

<u>Step-by-step explanation:</u>

(476 - 560) : 560 x 100

= (476 : 560 - 1)100

= 85 - 100 = - 15

Therefore, - 15% did the candle sales decrease.

4 0

3 years ago

Checking my work. which one?

Genrish500 [490]

Answer:

Dividing exponents you subtract.

3^8/3^5 = 3^3

3^3

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(3^3)^3 = <u>3^9</u>

<h2>Final Answer is $3^{9}$ </h2><h2 />

Apparently this makes no sense according to comments, if you want a more indepth look into exponents search "The properties of exponents".

6 0

2 years ago

Read 2 more answers

Solve the system of linear equations for x and y.(cos θ)x + (sin θ)y=1(−sin θ)x + (cos θ)y = 0x=y=

lys-0071 [83]

Answer:

$\bold{x =cos\theta}\\\bold{y=sin\theta}$

Step-by-step explanation:

The given system of linear equations is:

$(cos\theta)x+(sin\theta)y=1\\(-sin\theta)x+(cos\theta)y=0$

We have to solve the equations for the values of $x, y$ .

Let us use elimination method in which we eliminate one of the variables from the two variables.

For this, let us multiply the first equation by $sin\theta$ and second equation by $cos\theta$

Now, the equations become:

$(cos\theta.sin\theta)x+(sin\theta.sin\theta)y=sin\theta\\\Rightarrow (cos\theta.sin\theta)x+(sin^2\theta)y=sin\theta ....... (1)\\\\(-sin\theta.cos\theta)x+(cos\theta.cos\theta)y=0\\\Rightarrow (-sin\theta.cos\theta)x+(cos^2\theta)y=0 ..... (2)$

Now, let us add (1) and (2):

$(sin^2\theta)y+(cos^2\theta)y=sin\theta\\\Rightarrow (sin^2\theta+cos^2\theta)y=sin\theta\\\Rightarrow (1)y=sin\theta\\\Rightarrow y = sin\theta$

Using the equation:

$(-sin\theta)x+(cos\theta)y=0$

Putting value of $y$ :

$\Rightarrow (-sin\theta)x+(cos\theta)sin\theta=0\\\Rightarrow (sin\theta)x=(cos\theta)sin\theta\\\Rightarrow x = cos\theta$

So, the answer to the system of linear equations is:

$\bold{x =cos\theta}\\\bold{y=sin\theta}$

7 0

3 years ago

PLS HELP WITH THESE THREE NO LINKS

Westkost [7]

Answer:

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Step-by-step explanation:

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2 years ago