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sleet_krkn [62]
3 years ago
12

A number when divided by 780 gives remainder 38 .What

Mathematics
1 answer:
baherus [9]3 years ago
4 0

Given:

A number when divided by 780 gives remainder 38.

To find:

The reminder that would be obtained by dividing same number by 26.

Solution:

According to Euclis' division algorithm,

a=bq+r                ...(i)

Where, q is quotient and 0\leq r is the remainder.

It is given that a number when divided by 780 gives remainder 38.

Substituting b=780,\ r=38 in (i), we get

a=(780)q+38

So, given number is in the form of 780q+38, where q is an integer.

On dividing 780q+38 by 26, we get

\dfrac{780q+38}{26}=\dfrac{780q}{26}+\dfrac{38}{26}

\dfrac{780q+38}{26}=30q+\dfrac{26+12}{26}

\dfrac{780q+38}{26}=30q+\dfrac{26}{26}+\dfrac{12}{26}

\dfrac{780q+38}{26}=30q+1+\dfrac{12}{26}

Since q is an integer, therefore (30q+1) is also an integer but \dfrac{12}{26} is not an integer. Here 26 is divisor and 12 is remainder.

Therefore, the required remainder is 12.

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Hope this helps! :D

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