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ra1l [238]
2 years ago
13

Which graph shows data whose r-value is most likely closest to 0?

Mathematics
2 answers:
Alexxandr [17]2 years ago
8 0

Answer:

D) A graph shows both axes unnumbered. Points are scattered all over the graph.

Step-by-step explanation:

The value of "r" tells you how strong the correlation is between the independent and dependent variables. If its close to 0, then there will be hardly any correlation, so a good example of this is the 4th option where there's no pattern in the data set.

kozerog [31]2 years ago
4 0

Answer:

B

Step-by-step explanation:

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Step-by-step explanation:

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3 years ago
Find cos theta if sin theta=3/4 and theta lies in quadrant 2
GaryK [48]
By the Pythagorean theorem, the missing side is -sqrt7. The definition of sin is side opposite over hypotenuse, so go into Q2 and make an angle and label the side opposite the angle with a 3 and the hypotenuse a 4. The other leg is -sqrt7 cuz x is negative in Q2. The cosine of an angle is the side adjacent over the hypotenuse, so the cos then is -sqrt7/4
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3 years ago
Complete the square to rewrite y-x^2-6x+14 in vertex form. then state whether the vertex is a maximum or minimum and give its co
ycow [4]

Answer:

y= x^2 -6x +(\frac{6}{2})^2 +14 -(\frac{6}{2})^2

And solving we have:

y= x^2 -6x +9 + 14 -9

y= (x-3)^2 +5

And we can write the expression like this:

y-5 = (x-3)^2

The vertex for this case would be:

V= (3,5)

And the minimum for the function would be 3 and there is no maximum value for the function

Step-by-step explanation:

For this case we have the following equation given:

y= x^2 -6x +14

We can complete the square like this:

y= x^2 -6x +(\frac{6}{2})^2 +14 -(\frac{6}{2})^2

And solving we have:

y= x^2 -6x +9 + 14 -9

y= (x-3)^2 +5

And we can write the expression like this:

y-5 = (x-3)^2

The vertex for this case would be:

V= (3,5)

And the minimum for the function would be 3 and there is no maximum value for the function

4 0
4 years ago
Which of the following equations can be used to find the length of angle LN in the triangle below?
shtirl [24]

Answer:

Option A. LN^{2}=33^{2}-11^{2}

Step-by-step explanation:

we know that

In the right triangle MNL

Applying the Pythagoras Theorem

MN^{2}=ML^{2} +LN^{2}

substitute the values

33^{2}=11^{2} +LN^{2}

LN^{2}=33^{2}-11^{2}

5 0
4 years ago
Please help me with these geometry questions.
sashaice [31]

Answer:

1)2(lb+bh+hl)

=2(17*12+12*8+8*17)

=2(204+96+136)

=2*436

=872 in^2

2)2*pi*r(r+h)

=2*3.14*14(14+29)

=6.28*14(43)

=6.28*14*43

=3780.56 mm^2

3)A=11*4.3+3*6 +3*8+11*3(Area of each plane figure -triangle and rectangle)

=47.3+18+24+33

=122.3cm^3

4)h*(sum of II sides)+14*8+19*8+14*8+25(Area of plane surface-trapezium,rectangle,square)

=12.1(19+5)+112+152+112+25

=12.1*24+401

=290.4+401

=691.4ft^2

7 0
3 years ago
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