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alexdok [17]
3 years ago
12

A bicycle computer or cyclometer uses a magnet counter that records each wheel rotation to calculate the bike’s total distance t

raveled. To set up the computer, you select a calibration constant for the bike’s wheel size. The computer multiplies this constant times the number of tire rotations to find the total distance in miles. Enter a function for the distance d in miles if the calibration number is 0.00125. If the function is incorrect and your tire is actually slightly smaller, how should the function change?
Mathematics
1 answer:
CaHeK987 [17]3 years ago
6 0

The simplest and probably the best way to understand this problem is to make up a problem that obeys what you have been given. It doesn't have to be realistic. It just has to obey the conditions. Let us suppose that you thought the diameter of the tire is 1 yard. That would mean the circumfrence is pi * d

C = 3.14 * 1

That would mean that the circumference is 3.14 yards. It would also mean that you would have to have the wheel turn 1760 yards / /3.14 yards / revolution which is about 561 revolutions / mile. So the way I have set up the problem, my equation is d = 561 * R where R is the number of revolutions.

Now let's see what happens when you say "O my Goodness, the wheel diameter is really 32 inches" which 0.8888888 yards  what happens now?

Now you still have to go 1760 yards How many revolutions is that?

C = pi * d

C = 3.14 * 0.88888888

C = 2.79111 yards

How many revolutions does it take to 1760 yards.

R = 1760 // 2.78111 yards / revolution

R = 631 revolutions / mile. What happened?

Your constant goes up if the wheel diameter goes down. Think about this. Do you ride a bicycle? I do. It makes perfect sense to me that if the wheel is small, it will have to turn more often to go a mile. No matter where that 0.00125 comes from or how it was derived, the constant will have to go up if the wheel gets smaller.


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(3, -5)

Step-by-step explanation:

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George's page contains twice as many type words as Bill's paid and Bill's page contains 50 fewer words and Charlie's page. If ea
defon
For this, we use simultaneous equations. Let George's page be g, Charlie's be c and Bill's page be b.

First, <span>George's page contains twice as many type words as Bill's.

Thus, g = 2b.

</span><span>Second, Bill's page contains 50 fewer words than Charlie's page.

Thus, b = c - 50.

</span>If each person can type 60 words per minute, after one minute (i.e. when 60 more words have been typed) <span>the difference between twice the number of words on bills page and the number of words on Charlie's page is 210.

We can express that as 2b - c = 210.

Now we need to find b, since it represents Bill's page.

We can substitute b for (c - 50) since b = c - 50, into the equation 2b - c = 210. This makes it 2(c - 50) - c = 210.

We can expand this to 2c - 100 - c = 210.

We can simplify this to c - 100 = 210.

Add 100 to both sides.

c - 100 + 100 = 210 + 100

Then simplify: c = 210 + 100 = 310.

Now that we know c, we can use the first equation to find b.

b = c - 50 = 310 - 50 = 260.

260 is your answer. I don't know where George comes into it. Maybe it's a red herring!</span>
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Answer:

24.75/24¾

Step-by-step explanation:

148.5 ÷ 6 = 24¾ or 24.75

Answer: Each driver drove 24.75/24¾ miles

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What is 8 2/5% of 75? Write your answer as a decimal
likoan [24]

Answer: 0.875

Step-by-step explanation:

The answer that has already been given is perfect in and by itself. I just want to give you some methods for doing these type of questions so that you won’t stagger when you see these type of questions in exams (like the SAT).

Whenever you see such questions, remember the following things. These are conversions of English words to Mathematical tools.

What

=

Any variable like

x

Percent / Percentage / %

=

Divide by 100

of

=

Multiply

is

=

Put an equal to (

=

) sign

I’ll give you an example through a question.

What percent of 200 is 5?

Ans: Replace English words by mathematical tools according to the rules I told you.

x

( What) /100 ( percent)

×

( of) 200

=

( is) 5

In a refined form,

x

100

×

200

=

5

Calculate x. On calculating, x comes out to be

2.5

So, 2.5 percent of 200 is 5.

Now your question is actually very simple if you follow my rules.

You want 87.5%. By the rules, % means divided by 100. So

87.5

%

=

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100

and now using the same strategy, Ans:

875

1000

Disregard the next section if you know how to convert a decimal to a fraction

Section Starts

First, I’ll write the decimal form. Whenever you divide by a number that is in form of 1 followed by

n

number of zeroes. (here 1 is followed by 2 zeroes), you should shift the decimal point to the left side by n places.

In this case, shift decimal point in 87.5 to the left by 2 places. So this becomes 0.875.

This is the answer in decimal point.

Now simultaneously, I’ll teach you how to convert a decimal into a fraction.

Here, you see 2 types of “numbers”. One to the left side of the decimal point and one to the right side of the decimal point.

Here, left side of decimal point is 0 and right side of decimal point is 875.

Count the number of digits in the number to the right side of the decimal point (Here, the number of digits is 3)

Remove the decimal point and divide the number by a number formed by 1 followed by the “digits” we obtained (i.e. 3).

So, 875/1000. Simplify this, and you get your answer.

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