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2 years ago

6th Grade Math

Mathematics

2 answers:

Elena L [17]2 years ago

6 0

Formula of area of triangle-1/2

The base is 20+37 =57

so the answer is 1/2*57*14

bonufazy [111]2 years ago

5 0

Answer:

A. 1/2 x 14 x 57

Step-by-step explanation:

The formula for the area of a triangle is base x height x 1/2

To calculate the base you would need to add the two numbers on the bottom of the triangle: 20 + 37 = 57

The photo shows that the height is 14 so it would be

1/2 x 14 x 57

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Paladinen [302]

3 cm/h easy peasy

Step-by-step explanation:

12 cm in 4 hrs
For 1 cm : 12/4 = 3 cm

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2 years ago

The corners of the vertices of CDE are c(1,4) d(3,7) e(7,4). if a triangle is reflected over the line y=3 what are the coordinat

skelet666 [1.2K]

The answer is (3,-1)

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3 years ago

If a ball is thrown straight up into the air with an initial velocity of 70 ft/s, its height in feet after t seconds is given by

Vitek1552 [10]

Answer:

a) Average velocity at 0.1 s is 696 ft/s.

b) Average velocity at 0.01 s is 7536 ft/s.

c) Average velocity at 0.001 s is 75936 ft/s.

Step-by-step explanation:

Given : If a ball is thrown straight up into the air with an initial velocity of 70 ft/s, its height in feet after t seconds is given by $y = 70t-16t^2$ .

To find : The average velocity for the time period beginning when t = 2 and lasting. a. 0.1 s. , b. 0.01 s. , c. 0.001 s.

Solution :

a) The average velocity for the time period beginning when t = 2 and lasting 0.1 s.

$(\text{Average velocity})_{0.1\ s}=\frac{\text{Change in height}}{0.1}$

$(\text{Average velocity})_{0.1\ s}=\frac{h_{2.1}-h_2}{0.1}$

$(\text{Average velocity})_{0.1\ s}=\frac{(70(2.1)-16(2.1)^2)-(70(0.1)-16(0.1)^2)}{0.1}$

$(\text{Average velocity})_{0.1\ s}=\frac{69.6}{0.1}$

$(\text{Average velocity})_{0.1\ s}=696\ ft/s$

b) The average velocity for the time period beginning when t = 2 and lasting 0.01 s.

$(\text{Average velocity})_{0.01\ s}=\frac{\text{Change in height}}{0.01}$

$(\text{Average velocity})_{0.01\ s}=\frac{h_{2.01}-h_2}{0.01}$

$(\text{Average velocity})_{0.01\ s}=\frac{(70(2.01)-16(2.01)^2)-(70(0.01)-16(0.01)^2)}{0.01}$

$(\text{Average velocity})_{0.01\ s}=\frac{75.36}{0.01}$

$(\text{Average velocity})_{0.01\ s}=7536\ ft/s$

c) The average velocity for the time period beginning when t = 2 and lasting 0.001 s.

$(\text{Average velocity})_{0.001\ s}=\frac{\text{Change in height}}{0.001}$

$(\text{Average velocity})_{0.001\ s}=\frac{h_{2.001}-h_2}{0.001}$

$(\text{Average velocity})_{0.001\ s}=\frac{(70(2.001)-16(2.001)^2)-(70(0.001)-16(0.001)^2)}{0.001}$

$(\text{Average velocity})_{0.001\ s}=\frac{75.936}{0.001}$

$(\text{Average velocity})_{0.001\ s}=75936\ ft/s$

5 0

3 years ago

Which answer is the slope-intercept form for the given equation?<br><br> 13x+2y=43

yanalaym [24]

Y=-13/2x+43/2 I hope this helped :3

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3 years ago

Read 2 more answers

Pls help right now need pleaseee

andrezito [222]

Answer:

-1/2

Step-by-step explanation:

The cosine is equal to the x coordinate of the point where the terminal side of the angle intersects the unit circle.

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1 year ago