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3 years ago

PLEASE HELP!!!! -or show me where i can get this answer online A B C D

Mathematics

2 answers:

statuscvo [17]3 years ago

4 0

Answer: C

Step-by-step explanation:

Standard form for multi-variable expession( quadratic, trinomial, polynomial, etc) are represented by something like this.

ax^2+ bx+c, which means the stating term is the degree or exponet with the highest number then as we go right the degree go smaller.

So that means 5x^4 will be the starting term so a and b are ruled out. The next term will be x squared o x^2 so the only answer that has it second is C

liq [111]3 years ago

3 0

Answer:

The answer is C

Step-by-step explanation:

You might be interested in

Simplify cos^2 A/1+sin A

Stels [109]

Answer:

$\displaystyle \frac{\cos^2(A)}{1+\sin(A)}=1-\sin(A)$

Step-by-step explanation:

We want to simplify:

$\displaystyle \frac{\cos^2(A)}{1+\sin(A)}$

Recall the Pythagorean Identity:

$\sin^2(A)+\cos^2(A)=1$

So:

$\cos^2(A)=1-\sin^2(A)$

Substitute:

$\displaystyle =\frac{1-\sin^2(A)}{1+\sin(A)}$

Factor. We can use the difference of two squares pattern:

$\displaystyle =\frac{\left(1-\sin(A))(1+\sin(A))}{1+\sin(A)}$

Cancel. Hence:

$\displaystyle \frac{\cos^2(A)}{1+\sin(A)}=1-\sin(A)$

7 0

3 years ago

PLEASE HELP !! ILL GIVE BRAINLIEST !!

son4ous [18]

Answer:

<YXZ and <TUS

Step-by-step explanation:

An exterior angle is found outside the parallel line. When you have two exterior angles that are opposite each other along the transversal, they are referred to as alternate exterior angles.

Therefore, the only pair of angles from the given options that flare alternate exterior angles are:

<YXZ and <TUS

4 0

3 years ago

Quadrilateral ABCD has diagonals that are congruent and perpendicular to each other. What classification can be given to ABCD?

mash [69]

Rhombus is a quadrilateral that has 4 congruent sides and diagonals bisect angles and diagonals which are perpendicular. Squares, rectangles and parallelograms do not have diagonals that are perpendicular. Answer thus is C. rhombus

5 0

3 years ago

Could someone please answer this? :) thank you

malfutka [58]

Answer:

The last one

Step-by-step explanation:

What we know:

We have a total of 16 coins

The 16 coins consist of dimes and quarters

The value of the coins is 3.10

The value of a dime is .10

The value of a quarter is .25

Using this information we can create a system of linear equations

First off we know that we have a total of 16 coins which consist of dimes and quarters

The number of Quarters can be represented by q and then number of dimes can be represented by d.

If we have a total of 16 coins then q + d must equal 16

So equation 1 is q + d = 16

Now we need to create a second equation

We know that the total value of the coins is 3.10 and we know that the coins consist of dimes and quarters

As you may know a quarter has a value of .25 cents and a dime has a value of 10 cents

If the total value of the coins is 3.10 the the number of dimes (d) times .10 + the number of Quarters times .25 must equal 3.10

This can also be written as

.25q + .10d = 3.10

So the two equations are

q + d = 16 and .25q + .10d = 3.10

These equations are shown in the last answer choice

Note: b is very similar to d

However the the value of the coins are incorrect in B

In B the value of the dime is represented by 10 which is not correct because the value of a dime is .10 not 10

6 0

3 years ago

In the △PQR, PQ = 39 in, PR = 17 in, and the altitude PN = 15 in. Find QR.

romanna [79]

Altitude = 90* Angle

15^2+b^2 = 39^2
225+b^2 = 1521
1296 = b^2
36= b

15^2 + b^2 = 17^2
225 +b^2 = 289
64 = b^2
8 = b

36 + 8 = 44

39+17 = 56

56 is greater then 44

Triangle Inequality Theorem Proves

So QR = 44

8 0

3 years ago

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