Aline segment may have more than one midpoint.<br> A. True<br> B. False

¿cuáles son los criterios de congruencia y semejanza de triángulo?

mars1129 [50]

Answer:

Two triangles are similar if they meet one of the following criteria. : Two pairs of corresponding angles are equal. : Three pairs of corresponding sides are proportional. : Two pairs of corresponding sides are proportional and the corresponding angles between them are equal.

Dos triángulos son similares si cumplen uno de los siguientes criterios. : Dos pares de ángulos correspondientes son iguales. : Tres pares de lados correspondientes son proporcionales. : Dos pares de lados correspondientes son proporcionales y los ángulos correspondientes entre ellos son iguales.

Step-by-step explanation:

3 0

3 years ago

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I need help before time run out

valentina_108 [34]

The answer is D. You are just adding 8 to the number of hours you work because you earn 8 dollars an hour, or you can just multiply the number of hours by the wage you get paid and you would get the your gross pay. It would also be in quadrant 1 because all the numbers are positive and quadrant 1 is all positive numbers not like the other quadrants where there is either all negative numbers or some positive numbers and some negative numbers. But to make things shorter the answer is D.

6 0

3 years ago

Assume that you have a sample of n 1 equals 6, with the sample mean Upper X overbar 1 equals 50, and a sample standard deviati

tigry1 [53]

Answer:

$t=\frac{(50 -38)-(0)}{7.46\sqrt{\frac{1}{6}+\frac{1}{5}}}=2.656$

$df=6+5-2=9$

$p_v =P(t_{9}>2.656) =0.0131$

Since the p value is higher than the significance level given of 0.01 we don't have enough evidence to conclude that the true mean for group 1 is significantly higher thn the true mean for the group 2.

Step-by-step explanation:

Data given

$n_1 =6$ represent the sample size for group 1

$n_2 =5$ represent the sample size for group 2

$\bar X_1 =50$ represent the sample mean for the group 1

$\bar X_2 =38$ represent the sample mean for the group 2

$s_1=7$ represent the sample standard deviation for group 1

$s_2=8$ represent the sample standard deviation for group 2

System of hypothesis

The system of hypothesis on this case are:

Null hypothesis: $\mu_1 \leq \mu_2$

Alternative hypothesis: $\mu_1 > \mu_2$

We are assuming that the population variances for each group are the same

$\sigma^2_1 =\sigma^2_2 =\sigma^2$

The statistic for this case is given by:

$t=\frac{(\bar X_1 -\bar X_2)-(\mu_{1}-\mu_2)}{S_p\sqrt{\frac{1}{n_1}+\frac{1}{n_2}}}$

The pooled variance is:

$S^2_p =\frac{(n_1-1)S^2_1 +(n_2 -1)S^2_2}{n_1 +n_2 -2}$

We can find the pooled variance:

$S^2_p =\frac{(6-1)(7)^2 +(5 -1)(8)^2}{6 +5 -2}=55.67$

And the pooled deviation is:

$S_p=7.46$

The statistic is given by:

$t=\frac{(50 -38)-(0)}{7.46\sqrt{\frac{1}{6}+\frac{1}{5}}}=2.656$

The degrees of freedom are given by:

$df=6+5-2=9$

The p value is given by:

$p_v =P(t_{9}>2.656) =0.0131$

Since the p value is higher than the significance level given of 0.01 we don't have enough evidence to conclude that the true mean for group 1 is significantly higher thn the true mean for the group 2.

4 0

3 years ago

One number is seven less than five times another. If their sum is decreased by four the result is one. Find the numbers

juin [17]

Let the number be Y .
Y is seven
less than 5 times another (let that other be X)
Y=7-5X
sum of both Y and X minus 4 gives one
Y+X-4=1
now solve both equations .

6 0

2 years ago

Please help!! I'll give brainliest! <br>Identifying Triangle Congruence

ddd [48]

Answer:

1. SAS

2. SSS

3. ASA

4. AAS

5. RHS

7 0

3 years ago

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Aline segment may have more than one midpoint. A. True B. False