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3 years ago

Please help, it's urgent!

Mathematics

2 answers:

qaws [65]3 years ago

7 0

It’s answer choice number one x-+5,y

KengaRu [80]3 years ago

4 0

It’s the first answer choice... the translation was 5 units to the right (horizontal movement so it affects the x) and it’s to the right (which makes it a positive 5). It didn’t move up or down so the y stays the same

Hope it helps

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Evaluate the line integral, where C is the given curve. (x + 6y) dx + x2 dy, C C consists of line segments from (0, 0) to (6, 1)

Dima020 [189]

Split $C$ into two component segments, $C_1$ and $C_2$ , parameterized by

$\mathbf r_1(t)=(1-t)(0,0)+t(6,1)=(6t,t)$

$\mathbf r_2(t)=(1-t)(6,1)+t(7,0)=(6+t,1-t)$

respectively, with $0\le t\le1$ , where $\mathbf r_i(t)=(x(t),y(t))$ .

We have

$\mathrm d\mathbf r_1=(6,1)\,\mathrm dt$

$\mathrm d\mathbf r_2=(1,-1)\,\mathrm dt$

where $\mathrm d\mathbf r_i=\left(\dfrac{\mathrm dx}{\mathrm dt},\dfrac{\mathrm dy}{\mathrm dt}\right)\,\mathrm dt$

so the line integral becomes

$\displaystyle\int_C(x+6y)\,\mathrm dx+x^2\,\mathrm dy=\left\{\int_{C_1}+\int_{C_2}\right\}(x+6y,x^2)\cdot(\mathrm dx,\mathrm dy)$

$=\displaystyle\int_0^1(6t+6t,(6t)^2)\cdot(6,1)\,\mathrm dt+\int_0^1((6+t)+6(1-t),(6+t)^2)\cdot(1,-1)\,\mathrm dt$

$=\displaystyle\int_0^1(35t^2+55t-24)\,\mathrm dt=\frac{91}6$

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3 years ago

12 2/5 - 4 4/6 in whole numbers & fractions

Artist 52 [7]

12 2/5 - 4 4/6 = ?
Whole number: It cannot be a whole number, since it is a repeating decimal. As a repeating decimal, it is 7.7333333333333 and so on. If you round it to the ones place, it would become 8. As a simplified decimal, it would be 7.7

Fraction: 7 11/15

HOPE THIS HELPED. ;-)

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Answer:

Step-by-step explanation:

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