Option a, c,d are correct.
step-by-step explanation:
from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have
tz=sz(given)
bz=zb(common)
therefore, by rhs rule,δtzb ≅δszb
by cpctc, sz≅tz
also, from δctz and δasz,
tz=sz(given)
∠tcz=∠saz(90°)
by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz
also,from δasz and δzsb,
zs=sz(common)
∠zbs=∠saz=90°
by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb
hence, option a, c,d are correct.
Answer:
b = c− 3a/2
Step-by-step explanation:
Since we do not have any values for
a
or
c
all that we can do is solve for b Subtract 3a from both sides then divide by 2
Remember, SF= new/old. On shape 2, the side with the length 3 corresponds to the length of 9 on shape 1. (SF=3/9)=0.3333333....
Answer:
86/3=28.67
Step-by-step explanation:
You can just use the tn formula to solve this tn= t1 + (n-1)d
