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spin [16.1K]
3 years ago
9

The sum of a number and twice another number is 17. The sum of twice the first number and the second number is 4. What are the t

wo numbers?
a) define the variables

b) write a system of equations

c) solve by elimination
Mathematics
1 answer:
zhannawk [14.2K]3 years ago
8 0

Step-by-step explanation:

Given that,

a + 2b = 17

Also,

2a + b = 4

By adding the above expressions we get,

a + 2b + 2a + b = 17 + 4

3a + 3b = 21.

3 (a + b) = 21

a + b = 21/3

a + b = 7 Let us take 'b' = 10

a + 10 = 7

a = 7 - 10

a = -3

Now let's check by verifying by putting a = -3 and b = 10 in the previous expressions

a + 2b = 17

-3 + (2 × 10) = 17

-3 + 20 = 17

17 = 17

2a + b = 4

(2 × -3) + 10 = 4

-6 + 10 = 4

4 = 4

Therefore, a = -3 and b = 10 [(-3,10)] is the solution.

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Hello from MrBillDoesMath!

Answer:

(x+2) ( x^2 + 3)

Discussion:

x^3 + 2x^2 + 3x + 6 =  

( x^3 + 2x^2) + (3x + 6) =         => factor "x^2" from the first term; factor 3

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I need help with these
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Let x be the number.
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