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algol13
3 years ago
14

Reflect the x axis A B C D

Mathematics
1 answer:
Ronch [10]3 years ago
3 0

Answer:

see explanation

Step-by-step explanation:

Under a reflection in the x- axis

a point (x, y ) → (x, - y ) , then

A (- 1, - 17 ) → A' (- 1, 17 )

B (0, - 12 ) → B' (0, 12 )

C (- 5, - 11 ) → C' (- 5, 11 )

D (- 6, - 16 ) → D' (- 6, 16 )

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Read 2 more answers
In trapezoid $ABCD$, $\overline{AB}$ is parallel to $\overline{CD}$, $AB = 7$ units, and $CD = 10$ units. Segment $EF$ is drawn
Mekhanik [1.2K]

Answer:

EF = 58/7

Step-by-step explanation:

If you extend both BC and AD to meet at P you get 3 similar triangles PAB, PEF, and PCD. Let's call BF = 3x and FC = 4x. Therefore the following proportions can be expressed:

BP/7 = (BP+7x)/10

10BP = 7*(BP+7x)

10BP = 7BP+49x

3BP = 49x

BP = (49/3)x

BP/7 = (BP+3x)/EF

EF = (BP+3x)*7/BP

EF = ((49/3)x + 3x)*7/((49/3)x)

EF = ((58/3)x*7*3)/(49x)

EF = 58/7

3 0
3 years ago
Isolate x in 4x+4y=12
e-lub [12.9K]
4x+4y=12
(-4y) (-4y)
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