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Natali5045456 [20]
3 years ago
10

Given: B (3, -9) , and C(11,6) what is the segment BC

Mathematics
1 answer:
Andrej [43]3 years ago
8 0

Answer:

B

Step-by-step explanation:

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The answer is 0.857 in decimal form

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Horizontal translation
vampirchik [111]

Answer:

The correct option is;

Reflection over the y-axis

Step-by-step explanation:

An even function is a function that satisfies the following function equation;

f(x) = f(-x)

Therefore, for an even function, we have;

f(x) - f(-x) = 0

Which gives that the values of f(x) of the even function is the same upon reflection about the y-axis whereby the values of x changes from x to -x

Therefore, the symmetry of an even function is about the y-axis

However, an odd function is a function that satisfies the following function equation;

f(-x) = -f(x)

Therefore, reflection across the y-axis will result in an inversion of the odd function such that the odd function is not symmetrical about the y-axis as we have;

f(-x) = -f(x) ≠ f(x) which simplifies to f(x) ≠ f(-x).

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4 years ago
A private plane can hold 14 students. If there are 2,147 students going on a trip, how many private planes will need to be used
djyliett [7]

Answer:153.357

Step-by-step explanation:

8 0
3 years ago
Using Cramer’s Rule, what is the value of y in the system of linear equations below?
Vadim26 [7]

for the system of equations

a_1x+b_1y=c_1 \\a_2x+b_2y=c_2

the three matrices needed to use Cramer's Rule are:

D=\left[\begin{array}{cc}a_1&b_1\\a_2&b_2\end{array}\right] \\\\D_x=\left[\begin{array}{cc}c_1&b_1\\c_2&b_2\end{array}\right] \\\\D_y=\left[\begin{array}{cc}a_1&c_1\\a_2&c_2\end{array}\right].

To use Cramer's Rule we have to calculate the three determinants listed below of the matrices listed below.

D=\left[\begin{array}{cc}2&5\\-3&-2\end{array}\right] \\\\D_x=\left[\begin{array}{cc}-13&5\\3&-2\end{array}\right] \\\\D_y=\left[\begin{array}{cc}2&-13\\-3&3\end{array}\right] .

The value of the determinants are shown below.

det(D)=(2)(-2)-(-3)(5)=-4+15=11\\det(D_x)=(-13)(-2)-(3)(5)=26-15=11\\det(D_y)=(2)(3)-(-3)(-13)=6-39=-33\\

The value of y is \frac{det(D_y)}{det(D)}=-\frac{33}{11} =-3..

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4 years ago
Adult tickets to the fall play cost $8 and student tickets cost $4. The drama class sold 30 more adult tickets than student tick
bagirrra123 [75]
If you were to multiply 8 into 30 you'd get it.
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