All categories

2 years ago

What is 0.8% of 50? A. 0.04 B. 0.4 C. 4 D. 40

Mathematics

2 answers:

BaLLatris [955]2 years ago

7 0

Answer:

It would be A!

Step-by-step explanation:

.08 times .50 would be 0.04. (It's a quick way to be able to solve problems similar to that! :)

Mkey [24]2 years ago

4 0

Answer: B. (.4)

Step-by-step explanation:

Divide .8 by 100 to find the decimal you’re working with (.008) then do that number times 50 and you get .4.

You might be interested in

There are 4 types of the questions on Mrs. Moore's English final exam. The percent of each type of the question is shown in the

Verdich [7]

Jesse, to answer this, we need to see the graph. I'd help if I could! You can message me if you post it! :D

7 0

2 years ago

there are 14 girls trying out for volleyball. Each team will have six players. How many four teams will be made?

nikdorinn [45]

Answer:

Step-by-step explanation:

14 divided by 6 = 2.33333333

only 6 in a group so you round it

and you get 2

3 0

2 years ago

SOLVE THIS PLEASE !!!!!!!!!!!!

irinina [24]

Answer:

x would be 15/2 or 7.5

Step-by-step explanation:

7 0

2 years ago

Read 2 more answers

the diameter of a spherical basketball is 10 inches what is the volume of the basketball give the exact solution or round your a

DiKsa [7]

Volume of a sphere is 4/3(pi r ^3)

You were given d = 10 so r = 5

Then just plug and chug

7 0

2 years ago

Read 2 more answers

An insurance company sells automobile liability and collision insurance. Let X denote the percentage of liability policies that

qaws [65]

Answer:

-764.28

Step-by-step explanation:

Given the joint cumulative distribution of X and Y as

$F(x,y) = \frac{xy(x+y)}{2000000}\ \ \ \, \ 0\leq x100, 0\leq y\leq 100$

#First find $F_x$ and probability distribution function , $f_x(x)$ :

$F_x(x)=F(x,100)\\\\\\=\frac{100x(x+100)}{2000000}\\\\\\\\=\frac{100x^2+10000x}{2000000}\\\\\\=>f_x(x)=\frac{x}{10000}+\frac{1}{200}$

#Have determined the probability distribution unction , $f_x(x)$ , we calculate the Expectation of the random variable X:

$E(X)=\int\limits^{100}_0 \frac{x^2}{10000}+\frac{x}{200} dx \\\\\\\\=|\frac{x^3}{30000}+\frac{x^2}{400}|\limits^{100}_0\\\\=58.33\\\\$

#We then calculate $E(X^2)$ :

$E(X^2)=\int\limits^{100}_0 \frac{x^3}{10000}+\frac{x^2}{200}\ dx\\\\=\frac{x^4}{40000}+\frac{x^3}{600}|\limits^{100}_0=4166.67\\\\Var(X)=E(X^2)-(E(X))^2=4166.67-58.33^2\\\\Var(X)=764.28$

Hence, the Var(X) is 764.28

4 0

3 years ago