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3 years ago

Giving 100 points if someone can answer this correctly...

Mathematics

1 answer:

RUDIKE [14]3 years ago

7 0

Answer:

3813.6

Step-by-step explanation:

90.8 x 42 = 3813.6

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Kyra is traveling to Canada and will exchange $250 into Canadian dollars. The current exchange rate of $1 US is equal to $1.03 C

Margaret [11]

Answer:

She will get $275.50 in return

Step-by-step explanation:

250 x 1.03 = 257.50

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2 years ago

HELP PLEASE I ONLY GOT TODAY I NEED HELP ON 41,42,43, and 44 PLEASE HELP ME I NEED THIS TO GET MY GRADE UP

Daniel [21]

Answer:

Step-by-step explanation:

41. -3

42. 3

43 y^19

7 0

3 years ago

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marissa [1.9K]

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3 years ago

Resistors are labeled 100 Ω. In fact, the actual resistances are uniformly distributed on the interval (95, 103). Find the mean

Zinaida [17]

Answer:

$E[R]$ = 99 Ω

$\sigma_R$ = 2.3094 Ω

P(98<R<102) = 0.5696

Step-by-step explanation:

The mean resistance is the average of edge values of interval.

Hence,

The mean resistance, $E[R] = \frac{a+b}{2} = \frac{95+103}{2} = \frac{198}{2}$ = 99 Ω

To find the standard deviation of resistance, we need to find variance first.

$V(R) = \frac{(b-a)^2}{12} =\frac{(103-95)^2}{12} = 5.333$

Hence,

The standard deviation of resistance, $\sigma_R = \sqrt{V(R)} = \sqrt5.333$ = 2.3094 Ω

To calculate the probability that resistance is between 98 Ω and 102 Ω, we need to find Normal Distributions.

$z_1 = \frac{102-99}{2.3094} = 1.299$

$z_2 = \frac{98-99}{2.3094} = -0.433$

From the Z-table, P(98<R<102) = 0.9032 - 0.3336 = 0.5696

5 0

3 years ago

Ten experts rated a newly developed chocolate chip cookie on a scale of 1 to 50. Their ratings were: 34, 35, 41, 28, 26, 29, 32,

miskamm [114]

The mean deviation of the ratings is 4.12

Explanation

The ratings of the ten experts are: 34, 35, 41, 28, 26, 29, 32, 36, 38 and 40

So, the mean of all ratings $=\frac{34+35+41+28+26+29+32+36+38+40}{10}= \frac{339}{10}=33.9$

The formula for Mean deviation $= \sum \frac{|x_{i}- \mu|}{N}$ , where $x_{i}$ is the given data from $i=1$ to $i=10$ , $\mu$ is the mean of the data and $N$ is the total number of data. So.....

$|x_{1}-\mu |= |34-33.9|=0.1\\ |x_{2}-\mu|=|35-33.9|=1.1\\ |x_{3}-\mu |=|41-33.9|=7.1\\ |x_{4}-\mu |=|28-33.9|=5.9\\ |x_{5}-\mu |=|26-33.9|=7.9\\ |x_{6}-\mu |=|29-33.9|=4.9\\|x_{7}-\mu |=|32-33.9|=1.9\\ |x_{8}-\mu |=|36-33.9|=2.1\\ |x_{9}-\mu |=|38-33.9|=4.1\\ |x_{10}-\mu |=|40-33.9|=6.1$

So, the Mean deviation $=\sum \frac{|x_{i}-\mu |}{N}=\frac{0.1+1.1+7.1+5.9+7.9+4.9+1.9+2.1+4.1+6.1}{10} = \frac{41.2}{10}=4.12$

4 0

3 years ago