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3 years ago

10

O no I accidentally made this 20 points

1 answer:

harkovskaia [24]3 years ago

8 0

Answer:

Step-by-step explanation:

nonproportional. doesn't pass through the origin, so it's not proportional

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The latest poll of 400 randomly selected residents showed that 288 of them are hoping that the old town cinema stays open on Mai

Varvara68 [4.7K]

The approximate margin of error is 4%.

Using the formula given and our information, we have:

$E=1.96\times \sqrt{\frac{\frac{288}{400}(1-\frac{288}{400})}{400}}
\\
\\=1.96\times \sqrt{\frac{0.72(1-0.72)}{400}}=1.96\times \sqrt{\frac{0.72(0.28)}{400}}
\\
\\=0.044\approx 0.04=4%$

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4 years ago

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White raven [17]

Answer:

It’s the 3rd one

Step-by-step explanation:

6 0

3 years ago

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Marge drove 348 miles in 4.5 hours. At that rate, how many miles could she drive in 10 hours?

creativ13 [48]

Marge would drive 773.33 miles in 10 hours

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3 years ago

An atomic nucleus has a charge of +40e. What is the magnitude of the electric field at a distance of 1.0 m from the center of th

ASHA 777 [7]

Answer:

$E=5.76\times 10^{-8}N/C$

Step-by-step explanation:

We are given that

Charge of atomic nucleus,q=+40 e= $40\times 1.6\times 10^{-19}C$

Because

1 e= $1.6\times 10^{-19} C$

Charge of atomic nucleus= $64\times 10^{-19}C$

Distance of charge form the center of nucleus=r=1 m

We have to find the magnitude of electric field at distance r

$E=\frac{Kq}{r^2}$

Where K= $9\times 10^9Nm^2/C^2$

Using the formula

$E=\frac{9\times 10^9\times 64\times 10^{-19}}{1}=576\times 10^{-10}N/C$

$E=\frac{576}{100}\times 10^2\times 10^{-10}=5.76\times 10^{2-10}=5.76\times 10^{-8}N/C$

Using identity $a^x\cdot a^y=a^{x+y}$

Hence, the magnitude of electric field= $E=5.76\times 10^{-8}N/C$

6 0

3 years ago

the cost of 1 small box of mixed organic vegetables is $ blank. the cost of 20 small boxes of mixed organic vegetables is $ blan

Katena32 [7]

Answer:

1 box is $20 and 20 boxes are 400$

Step-by-step explanation:

8 0

3 years ago