Plz rationalize it with steps

Your friend is wrapping 1 meter of twine around a spool with a 2-centimeter diameter. The spool is thin and accommodates only on

Kazeer [188]

Answer:

a) 6 complete times

b) 19.3%

Step-by-step explanation:

In every turn, the diameter of the twine increases 1 cm.

After the first turn, there is a total wrapped of 3.14*2=6.3 cm.

After the second turn, we have wrapped 6.3+3.14*(2+1)=15.7 cm.

If we continue with these algorithm, we have that after the 6th turn we have 84.8 cm wrapped. This is the last complete turn.

T = 0 D = 2 cm. Wrapped = 6.3 cm. Total wrapped = 6.3 cm.

T = 1 D = 3 cm. Wrapped = 9.4 cm. Total wrapped = 15.7 cm.

T = 2 D = 4 cm. Wrapped = 12.6 cm. Total wrapped = 28.3 cm.

T = 3 D = 5 cm. Wrapped = 15.7 cm. Total wrapped = 44 cm.

T = 4 D = 6 cm. Wrapped = 18.8 cm. Total wrapped = 62.8 cm.

T = 5 D = 7 cm. Wrapped = 22.0 cm. Total wrapped = 84.8 cm.

T = 6 D = 8 cm. Wrapped = 25.1 cm. Total wrapped = 110 cm.

There are left (100-84.8) = 15.2 cm to wrap around the twine, which has a 25.1 cm diameter by now.

The perimeter of the twine is 3.14*25.1=78.8 cm.

The percentage of a complete circle that the last wrapping of the twine will make is:

P = 15.2/78.8 = 0.193 = 19.3%

4 0

3 years ago

Enter the lengths of QS and TV QS= TV=

kicyunya [14]

3v + 2 = 7v
2 = 4v
1/2 = v

QS = 3v + 2
= 3(1/2)+ 2
= 1.5 + 2
= 3.5

TV = 7v
= 7(1/2)
= 3.5

5 0

3 years ago

If y = kx, what is the value of k if y = 20 and x = 0.4? A) 5 B) 8 C) 9.6 D) 50

mariarad [96]

Answer:

D) 50

20/0.4=50

Step-by-step explanation:

7 0

3 years ago

The difference between two numbers is 3.50. The lesser number is 1.65.

deff fn [24]

Answer:

5.15

Step-by-step explanation:

you add 3.50 and 1.65 to get the other number

5 0

3 years ago

) You are finally well!  But now your child is sick!  You know there have been mistakes in orders so you are on the internet t

rjkz [21]

Answer:

The doctor's dosage was not appropriate.

The right dosage is from 56.625 mg to 113.25 mg of Antibiotic to be given every 6 hour for the child with weight 25 lbs.

Step-by-step explanation:

It is given that 20 to 40 mg/kg/day is the recommended dosage.

Now, the doctor's order is 150 mg of antibiotic to be given every 6 hours. And my child weighs 25 lbs.

Now, 1 lb is equivalent to 0.453 kg.

So, my child's weight is (25 × 0.453) = 11.325 kg.

So, the doctor's order is 150 mg of antibiotic to be given every 6 hours for a child of weight 11.325 kg.

Hence, the dosage is [(150 × 4) ÷ 11.325] = 52.98 mg/kg/day.

So, this is not within the limit of 20 to 40 mg/kg/day.

Therefore, the doctor's dosage was not appropriate.

Now, let the appropriate dosage is x mg per every 6 hours for a child with weight 25 lbs i.e. 11.325 kg.

So, $20 \leq \frac{4x}{11.325} \leq 40$

⇒ $20\leq 0.3532x \leq 40$

⇒ $56.625 \leq x \leq 113.25$

So, the right dosage is from 56.625 mg to 113.25 mg of antibiotic to be given every 6 hours for the child with weight 25 lbs. (Answer)

5 0

3 years ago