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finlep [7]
3 years ago
6

Please help! 10 points

Mathematics
2 answers:
Julli [10]3 years ago
6 0
For
a
x
2
+
b
x
+
c
=
0
, the values of
x
which are the solutions to the equation are given by:
x
=
−
b
±
√
b
2
−
4
a
c
2
a
Substituting
9
for
a
;
6
for
b
and
1
for
c
gives:
x
=
−
6
±
√
6
2
−
(
4
⋅
9
⋅
1
)
2
⋅
9
x
=
−
6
±
√
36
−
36
2
⋅
9
x
=
−
6
±
√
0
2
⋅
9
x
=
−
6
±
0
2
⋅
9
x
=
−
6
18
x
=
−
1
3

RUDIKE [14]3 years ago
4 0

Answer:

1 real soultion

Step-by-step explanation:

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7 0
3 years ago
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Can someone help with this question? Thank u! :)
MatroZZZ [7]

Answer:

2.50

Step-by-step explanation:

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7 0
3 years ago
<img src="https://tex.z-dn.net/?f=x%5E2-11x%2B24%3D0" id="TexFormula1" title="x^2-11x+24=0" alt="x^2-11x+24=0" align="absmiddle"
Mashcka [7]
Your answer is x=-24/11
8 0
3 years ago
Reuben rented a truck for one day. There was a base fee of $15.99, and there was an additional charge of 86 cents for each mile
RUDIKE [14]

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Step-by-step explanation:

3 0
3 years ago
Given that f(x)=5x^3+ax^2-4x-2 and that (x-1) is a factor of f(x), find a.
stepladder [879]

Answer:

a=1

Step-by-step explanation:

Because x-1 is factor of f(x)

for x1=1, f(1)=0, then

f(1)=5*1^3+a*1^2-4*1-2=0

5*1+a*1-4-2=0

5+a-6=0

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5 0
3 years ago
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