Using the binomial distribution, it is found that there is a 0.4096 = 40.96% probability that he answers exactly 1 question correctly in the last 4 questions.
<h3>What is the binomial distribution formula?</h3>
The formula is:
![P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}](https://tex.z-dn.net/?f=P%28X%20%3D%20x%29%20%3D%20C_%7Bn%2Cx%7D.p%5E%7Bx%7D.%281-p%29%5E%7Bn-x%7D)
![C_{n,x} = \frac{n!}{x!(n-x)!}](https://tex.z-dn.net/?f=C_%7Bn%2Cx%7D%20%3D%20%5Cfrac%7Bn%21%7D%7Bx%21%28n-x%29%21%7D)
The parameters are:
- x is the number of successes.
- n is the number of trials.
- p is the probability of a success on a single trial.
Considering that there are 4 questions, and each has 5 choices, the parameters are given as follows:
n = 4, p = 1/5 = 0.2.
The probability that he answers exactly 1 question correctly in the last 4 questions is P(X = 1), hence:
![P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}](https://tex.z-dn.net/?f=P%28X%20%3D%20x%29%20%3D%20C_%7Bn%2Cx%7D.p%5E%7Bx%7D.%281-p%29%5E%7Bn-x%7D)
![P(X = 1) = C_{4,1}.(0.2)^{1}.(0.8)^{3} = 0.4096](https://tex.z-dn.net/?f=P%28X%20%3D%201%29%20%3D%20C_%7B4%2C1%7D.%280.2%29%5E%7B1%7D.%280.8%29%5E%7B3%7D%20%3D%200.4096)
0.4096 = 40.96% probability that he answers exactly 1 question correctly in the last 4 questions.
More can be learned about the binomial distribution at brainly.com/question/24863377
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Slope intercept form is y=MX+b.
M is the slope, x is the x intercept, and b is the y intercept
the slope is
![\frac{ - 2}{1}](https://tex.z-dn.net/?f=%20%5Cfrac%7B%20-%202%7D%7B1%7D%20)
An intercept is where the formula crosses the axis. therefore, the x intercept is .5, and the y intercept is 1
so the point slope formula is
1. -4
2. 2
four plus negative four is zero and two minus two is zero
Answer: 0.31
Step-by-step explanation:
Let A denotes the event that the students report drinking alcohol and B denotes the students report using some type of tobacco product .
Given : P(A) =0.84 ; P(B)=0.33 and P(A∪B)=0.86
We know that ![P(A\cap B)=P(A)+P(B)-P(A\cup B)](https://tex.z-dn.net/?f=P%28A%5Ccap%20B%29%3DP%28A%29%2BP%28B%29-P%28A%5Ccup%20B%29)
Then, the probability that the student both drunk alcohol and used tobacco in the past month is given by :-
![P(A\cap B)=0.84+0.33-0.86=0.31](https://tex.z-dn.net/?f=P%28A%5Ccap%20B%29%3D0.84%2B0.33-0.86%3D0.31)
Hence, the probability that the student both drunk alcohol and used tobacco in the past month = 0.31
we are given that
both sides are equal
so, their length must be equal
![HK=\sqrt{(p-1)^2+(5-2)^2}](https://tex.z-dn.net/?f=%20HK%3D%5Csqrt%7B%28p-1%29%5E2%2B%285-2%29%5E2%7D%20%20)
![HK=\sqrt{(p-1)^2+9}](https://tex.z-dn.net/?f=%20HK%3D%5Csqrt%7B%28p-1%29%5E2%2B9%7D%20%20)
now, we can find other side
![JK=\sqrt{(p-7)^2+(5-2)^2}](https://tex.z-dn.net/?f=%20JK%3D%5Csqrt%7B%28p-7%29%5E2%2B%285-2%29%5E2%7D%20%20)
![JK=\sqrt{(p-7)^2+9}](https://tex.z-dn.net/?f=%20JK%3D%5Csqrt%7B%28p-7%29%5E2%2B9%7D%20%20)
now, we can set them equal
![HK=JK](https://tex.z-dn.net/?f=%20HK%3DJK%20%20)
![\sqrt{(p-1)^2+9}=\sqrt{(p-7)^2+9}](https://tex.z-dn.net/?f=%20%5Csqrt%7B%28p-1%29%5E2%2B9%7D%3D%5Csqrt%7B%28p-7%29%5E2%2B9%7D%20%20)
now, we can take square both sides
![(p-1)^2+9=(p-7)^2+9](https://tex.z-dn.net/?f=%20%28p-1%29%5E2%2B9%3D%28p-7%29%5E2%2B9%20%20)
now, we can solve for p
![(p-1)^2=(p-7)^2](https://tex.z-dn.net/?f=%20%28p-1%29%5E2%3D%28p-7%29%5E2%20%20)
![p^2-2p+1=p^2-14p+49](https://tex.z-dn.net/?f=%20p%5E2-2p%2B1%3Dp%5E2-14p%2B49%20%20)
![-2p+1=-14p+49](https://tex.z-dn.net/?f=%20-2p%2B1%3D-14p%2B49%20%20)
![12p=48](https://tex.z-dn.net/?f=%2012p%3D48%20%20)
..............Answer