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3 years ago

HELP HELP HELP HELP PLZ

Mathematics

2 answers:

Katena32 [7]3 years ago

7 0

Answer:

Step-by-step explanation:

3241004551 [841]3 years ago

3 0

I think it’s 10 I hope that helped

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For each pair figures, find the ratio of the area of the first figure to the area of the second. 14mm 7mm

Paraphin [41]

The ratio of the area of the first figure to the area of the second figure is 4:1

<h3>Ratio of the areas of similar figures </h3>

From the question, we are to determine the ratio of the area of the first figure to the area of the second figure

The two figures are similar

From one of the theorems for similar polygons, we have that

If the scale factor of the sides of two similar polygons is m/n then the ratio of the areas is (m/n)²

Let the base length of the first figure be ,m = 14 mm

and the base length of the second figure be, n = 7 mm

∴ The ratio of their areas will be

$(\frac{14 \ mm}{7 \ mm})^{2}$

$= \frac{196 \ mm^{2} }{49\ mm^{2} }$

$=\frac{4}{1}$

= 4:1

Hence, the ratio of the area of the first figure to the area of the second figure is 4:1

Learn more on Ratio of the areas of similar figures here: brainly.com/question/11920446

8 0

2 years ago

8. You are planning to use a ceramic tile design in your new bathroom. The tiles are blue-and-white equilateral triangles. You d

ira [324]

Step 1

Find the area of one equilateral triangle

Applying the law of sines

$Area=\frac{1}{2} *a*b*sin C$

in this problem

a=b=7 cm

C=60 degrees

$Area=\frac{1}{2} *7*7*sin 60$

$Area=\frac{1}{2} *49*\frac{\sqrt{3}}{2} \\ Area=49*\frac{\sqrt{3}}{4}$ cm²

Step 2

To calculate the area of the hexagon multiply the area of one equilateral triangle by $6$

$Area Hexagon=6*[49*\frac{\sqrt{3}}{4}] \\ Area Hexagon=73.5*\sqrt{3}$ cm²

therefore

the answer is the option

73.5 sqrt 3cm²

3 0

4 years ago

Read 2 more answers

Choose the equation that models the problem. Zach's baseball team won 32 games last season. They played a total of 45 games. How

hoa [83]

B
I + 32 = 45
hope this helps

4 0

3 years ago

X^2+y^2+14x+10y=7 center and radius

Sholpan [36]

$(x-a)^2+(y-b)^2=r^2\\\\(a;\ b)-the\ coordinates\ of\ the\ center\\r-the\ radius\\\\==================================\\Use:(k+l)^2=k^2+2kl+l^2\ (*)\\==================================$

$x^2+y^2+14x+10y=7\\\\x^2+14x+y^2+10y=7\\\\x^2+2x\cdot7+y^2+2y\cdot5=7\\\\\underbrace{x^2+2x\cdot7+7^2}_{Use\ (*)}-7^2+\underbrace{y^2+2y\cdot5+5^2}_{Use\ (*)}-5^2=7\\\\(x+7)^2-49+(y+5)^2-25=7\\\\(x+7)^2+(y+5)^2-74=7\ \ \ \ |add\ 74\ to\both\ sides\\\\(x+7)^2+(y+5)^2=81\\\\(x+7)^2+(y+5)^2=9^2$

$Answer:\\\boxed{(-7;-5)-center;\ 9-radius}$

8 0

3 years ago

Read 2 more answers

1). (-6p - 8) - (2p - 6) =

Alexeev081 [22]

Answer:

1.-8p-2

2.−4r−5

3.−7z−3

4.-3s-3

5. 1s

I got lazy to do the rest sorry :D

4 0

3 years ago