Answer:
The margin of error for the survey is 0.016
Step-by-step explanation:
We are given the following in the question:
Sample size, n = 1024
Sample proportion:

We have to find the margin of error associated with a 90% Confidence interval.
Formula for margin of error:


Putting the values, we get:

Thus, the margin of error for the survey is 0.016
P = what times 4 equals 1/2 = 1/8
I think the answer is maybe A?
The term that best describes a proof in which you assume the opposite of what you want to prove is proof of contradiction. Contradiction means opposite.
Your answer is: C) Proof of Contradiction
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